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 An aquarium is designing a new exhibit to showcase tropical fish. The exhibit will

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An aquarium is designing a new exhibit to showcase tropical fish. The exhibit will

include a tank that is a rectangular prism with a length l that is twice the width w. The volume of the tank is required to be 420. The space the aquarium has reserved for the exhibit is only 3 feet tall.

A: What is the width of the tank to the nearest tenth of a foot

B: How did you do it?

 Mar 9, 2015

Best Answer 

 #1
avatar+130516 
+5

Let the width  = W

Then the length is 2W

And L x W x H  = Volume

So we have

2W x W x 3 = 420    simplify

6W^2  = 420        divide both sides by 6

W^2  = 70            take the square root of both sides

W = √70 ft = about 8.4 ft

 

  

 Mar 9, 2015

1+0 Answers

 #1
avatar+130516 
+5
Best Answer

Let the width  = W

Then the length is 2W

And L x W x H  = Volume

So we have

2W x W x 3 = 420    simplify

6W^2  = 420        divide both sides by 6

W^2  = 70            take the square root of both sides

W = √70 ft = about 8.4 ft

 

  

CPhill Mar 9, 2015

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