+176 Jervin, Ken and Leon shared the cost of a gift for their friend. 1/5 of Jervin's and Leon's share was equal to 2/3 of Ken's share. 3/4 of Leon's share was equal to 1/3 of Jervin's and Ken's share. Leon paid $5 more than Ken. How much did the gift cost?
+313 Let Jervin share =A
Ken share = B
Leon share =C
From the given information,
1/5th of Jervin's and Leon's share equal to 2/3rd share of Ken's
1/5 (A+C)=2/3(B)
3A+3C=10B
3A-10B=-3C .........(1)
1/3th of Jervin's and Ken's share equal to 3/4rd share of Leon's
1/3 (A+B)=3/4 (C) .
4A+4B=9C .........(2)
And Leon paid 5 more than Ken
C=B+5
Solving (1) and (2)
4×(1)>>>12A-40B=-12C..........(3)
3×(1)>>>12A+12B=27C ...........(4)
(4)-(3)>>> (12A+12B)-(12A-40B)=27C+12C
52B=39C
4B=3C
Put C=B+5 in above equation
4B=3(B+5)
4B=3B+15
B=15
C=B+5
=15+5
=20
Put B and C in (2)
4A+4B=9C
4A+4(15)=9(20)
4A=180-60
4A=120
A=30
The gift cost=A+B+C
=30+15+20
=65
Answer: Gift cost is 65$
