As in, I have no idea how to recognize or solve them.
Like one example I was given was 9(2m-3)-squared +8=449. (Yay, variables.)
Haven't a clue how to go about solving for two solutions. Heck, I'm still shaky finding one. Please help?
+130544 I assume you have this :
9 ( 2m - 3)^2 + 8 = 449 our goal is just to end up with the (2m - 3)^2 part on the left side...so....
Subtract 8 from both sides
9 (2m - 3)^2 = 441
Divide both sides by 9
(2m - 3)^2 = 49
Now.....here's where we can use the square root property......take the square root of both sides.....but remember......on the right we need to take the plus and minus square root of 49.....so we will have two equations
2m - 3 = sqrt 49) and 2m - 3 = -sqrt (49)
And we have
2m - 3 = 7 and 2m - 3 = -7
Add 3 to both sides
2m = 10 and 2m = -4
Divide both sides by 2
m = 5 and m = -2
Pretty easy, huh ????
+130544 I assume you have this :
9 ( 2m - 3)^2 + 8 = 449 our goal is just to end up with the (2m - 3)^2 part on the left side...so....
Subtract 8 from both sides
9 (2m - 3)^2 = 441
Divide both sides by 9
(2m - 3)^2 = 49
Now.....here's where we can use the square root property......take the square root of both sides.....but remember......on the right we need to take the plus and minus square root of 49.....so we will have two equations
2m - 3 = sqrt 49) and 2m - 3 = -sqrt (49)
And we have
2m - 3 = 7 and 2m - 3 = -7
Add 3 to both sides
2m = 10 and 2m = -4
Divide both sides by 2
m = 5 and m = -2
Pretty easy, huh ????
