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find the area of the circle diameter is 35

 Mar 19, 2015

Best Answer 

 #2
avatar+1904 
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$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{r}}}^{{\mathtt{2}}}$$, $${\mathtt{d}} = {\mathtt{35}}$$

 

$${\mathtt{A}} = {\mathtt{Area}}$$, $${\mathtt{\pi}} = {\mathtt{3.141\: \!592\: \!653\: \!589\: \!793\: \!2}}$$..., r=1/2 the diameter

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\left({\mathtt{35}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)\right)}^{{\mathtt{2}}}$$

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{35}}}{{\mathtt{2}}}}\right)}^{{\mathtt{2}}}$$

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{35}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{35}}}{{\mathtt{2}}}}\right)$$

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1\,225}}}{{\mathtt{4}}}}\right)$$

 

$${\mathtt{A}} = {\frac{{\mathtt{1\,225}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{4}}}}$$ or $${\mathtt{A}} = {\mathtt{962.112\: \!750\: \!161\: \!874\: \!179\: \!3}}$$...

.
 Mar 19, 2015
 #1
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area = 961.625

 Mar 19, 2015
 #2
avatar+1904 
+5
Best Answer

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{r}}}^{{\mathtt{2}}}$$, $${\mathtt{d}} = {\mathtt{35}}$$

 

$${\mathtt{A}} = {\mathtt{Area}}$$, $${\mathtt{\pi}} = {\mathtt{3.141\: \!592\: \!653\: \!589\: \!793\: \!2}}$$..., r=1/2 the diameter

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\left({\mathtt{35}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)\right)}^{{\mathtt{2}}}$$

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{35}}}{{\mathtt{2}}}}\right)}^{{\mathtt{2}}}$$

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{35}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{35}}}{{\mathtt{2}}}}\right)$$

 

$${\mathtt{A}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1\,225}}}{{\mathtt{4}}}}\right)$$

 

$${\mathtt{A}} = {\frac{{\mathtt{1\,225}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{4}}}}$$ or $${\mathtt{A}} = {\mathtt{962.112\: \!750\: \!161\: \!874\: \!179\: \!3}}$$...

gibsonj338 Mar 19, 2015

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