Find the probability of drawing 4 white and two black b***s without replacement from a bag containing 1 red 4 black and 6 white b***s.
+130536 Find the probability of drawing 4 white and two black b***s without replacement from a bag containing 1 red 4 black and 6 white b***s.
The total number of ways to draw 6 things from 11 is given by C(11, 6) = 462
And we want to draw 4 of the 6 white ones= C(6,4) = 15 ways
And we want to write 2 of the 4 black ones = C(4, 2) = 6 ways
So we have [ 15 * 6 ] / 462 = 90 / 462 = about 19.5%
+130536 Find the probability of drawing 4 white and two black b***s without replacement from a bag containing 1 red 4 black and 6 white b***s.
The total number of ways to draw 6 things from 11 is given by C(11, 6) = 462
And we want to draw 4 of the 6 white ones= C(6,4) = 15 ways
And we want to write 2 of the 4 black ones = C(4, 2) = 6 ways
So we have [ 15 * 6 ] / 462 = 90 / 462 = about 19.5%
