Hello could someone help me with these questions
Find the indefinite integral of the following with respect to x:
Find the definite integral:
+130516 For the first one, we have
∫Be^6x dx let u = 6x du =6 dx du/6 = dx so we have
(B/6)∫e^u du =
(B/6) [ e^u] + C = (Be^6x) / 6 + C
For the second we have
∫6x^2 + 5x - 10 dx =
2x^3 + (5/2)x^2 - 10x from x = 1 to x = 3
[2(3)^3 + (5/2) (3)^2 - 10 (3) ] - [2(1)^3 + (5/2)(1)^2 - 10(1)] =
[54 + 45/2 - 30 ] - [2 + 5/2 - 10] =
52
+130516 For the first one, we have
∫Be^6x dx let u = 6x du =6 dx du/6 = dx so we have
(B/6)∫e^u du =
(B/6) [ e^u] + C = (Be^6x) / 6 + C
For the second we have
∫6x^2 + 5x - 10 dx =
2x^3 + (5/2)x^2 - 10x from x = 1 to x = 3
[2(3)^3 + (5/2) (3)^2 - 10 (3) ] - [2(1)^3 + (5/2)(1)^2 - 10(1)] =
[54 + 45/2 - 30 ] - [2 + 5/2 - 10] =
52
