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how can i find the inverse of 7^x, please

 Mar 12, 2015

Best Answer 

 #2
avatar+130516 
+5

We have 

f(x) = y = 7^x       take the log of both sides

log y  = log 7 ^x    and we can write

log y  = x log 7       divide both sides by log 7

log y / log 7  = x        exchange x and y

log x / log 7  = y        for y, write f-1(x)

 f-1(x) = log x / log 7

Here's the graph of  f(x) and its inverse

https://www.desmos.com/calculator/g3lyto49l0

 

  

 Mar 12, 2015
 #1
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0

It depends on which inverse you need.

An inverse "undoes" an operation. So for addition, it would be subtraction. 7x would then be -7x.

For multiplication, 7x would be (1/7x).

 Mar 12, 2015
 #2
avatar+130516 
+5
Best Answer

We have 

f(x) = y = 7^x       take the log of both sides

log y  = log 7 ^x    and we can write

log y  = x log 7       divide both sides by log 7

log y / log 7  = x        exchange x and y

log x / log 7  = y        for y, write f-1(x)

 f-1(x) = log x / log 7

Here's the graph of  f(x) and its inverse

https://www.desmos.com/calculator/g3lyto49l0

 

  

CPhill Mar 12, 2015

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