All Questions ⁺⁰237749 Questions

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520

1

Pythagorean Theorum

how do you find pythagorean theorum

Guest Feb 8, 2016

0

575

1

Hwk

Guest Feb 8, 2016

0

613

1

Absolute

how do i put in a absolute function?

Guest Feb 8, 2016

+5

720

1

+13

A student is asked to calculate the Pythagorean Triples for the number 13 using the identity (x^2-y^2)^2 + (2xy)^2 = (x^2 + y^2)^2. The student's steps are

A student is asked to calculate the Pythagorean Triples for the number 13 using the identity (x^2-y^2)^2 + (2xy)^2 = (x^2 + y^2)^2. The student's steps are shown below
Step 1: 13 = 7^2 - 6^2; therefore, x=7 and y=6
Step 2: (7^2 - 6^2)^2 read more ..

ddp123 Feb 8, 2016

0

995

2

+279

CyberQuestion

If you get this one right y get stars: is 32xa=22c whats the value of a

CyberSword12 Feb 8, 2016

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7510

1

what is the quarter of the number 40????????????????????????????????

what is the quarter of the number 40????????????????????????????????

Guest Feb 8, 2016

0

700

1

plz help me

Guest Feb 8, 2016

0

590

2

What is 22,284 divided 23,966?

What is 22,284 divided 23,966?

Guest Feb 8, 2016

0

1007

1

download calcalator

download calcalator

Guest Feb 8, 2016

0

668

1

+13

What is the value of k if x^3 + kx^2 + 7x + 5 is divided by x + 6 and gives a remainder of -1

What is the value of k if x^3 + kx^2 + 7x + 5 is divided by x + 6 and gives a remainder of -1
A.) 5
B.) -7
C.)7 read more ..

ddp123 Feb 8, 2016

0

816

2

???????????????????

What is 75 divided by 12?

Guest Feb 8, 2016

0

1020

2

Find the value of 53^3 using the identity (x+y)^3=x^3+3x^2y+3xy^2+y^2

Find the value of 53^3 using the identity (x+y)^3=x^3+3x^2y+3xy^2+y^2
Hint 53^3 =(50+3)^3; therefore, x=50, and y=3
I do not get this

Guest Feb 8, 2016

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486

0

-3x+y=-1

Guest Feb 8, 2016

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