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Find the vertex of the graph of the equation y=-2x^2+18x-15.

 May 19, 2021
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Find the vertex of the graph of the equation y=-2x^2+18x-15.

 

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\(f(x) = ax² + bx + c\\ y=-2x^2+18x-15\)

\(x_v=-\frac{p}{2}=-\frac{\frac{18}{-2}}{2}\\ \color{blue}x_v=4.5\)

\(y_v=q-\frac{p^2}{4}=\frac{-15}{-2}-\frac{(\frac{18}{-2})^2}{4}\\ y_v=-2x_v^2+18x_v-15=-2\cdot 4.5^2+18\cdot 4.5-15\\ \color{blue}y_v=25.5\)

Informed at:

https://www.arndt-bruenner.de/mathe/10/scheitelpunkt.htm

laugh  !

 May 20, 2021

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