$${\frac{{{log}}_{{\mathtt{5}}}{\left({\mathtt{625}}\right)}}{\left({\mathtt{17}}{\mathtt{\,\small\textbf+\,}}{\sqrt[{{\mathtt{{\mathtt{3}}}}}]{-{\mathtt{125}}}}\right)}}$$
log5(625) = 4 (because 54 = 625)
3√-125 = -5
so
$$\frac{\log_5{625}}{17+^3\sqrt{-125}}=\frac{4}{17-5}=\frac{1}{3}$$
.
