+0  
 
0
742
1
avatar+1904 

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{X}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{X}}}^{{\mathtt{2}}} = {\mathtt{0}}$$

 Apr 27, 2015

Best Answer 

 #1
avatar+23254 
+5

2x + x2  =  0

Factor out the x-term:

x(2 + x)  =  0

Two possible answers:

x  =  0     or     2 + x  =  0   --->   x  =  -2

 Apr 27, 2015
 #1
avatar+23254 
+5
Best Answer

2x + x2  =  0

Factor out the x-term:

x(2 + x)  =  0

Two possible answers:

x  =  0     or     2 + x  =  0   --->   x  =  -2

geno3141 Apr 27, 2015

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