+0

# Sum of squares - but I need power of 4

0
62
10
+34

I have this number:

84586075770624998147441974158189380700174460760744963832062282657

I generated it using this:

16515489654164894**4 + 10046498489496563**4

so its not square root (power of 2). Its power of 4.

Question: Its possible to compute which power of 4 form my original number and get back orig number? Its possible to do that using power of 2, but what about power of 4?

Apr 14, 2020

#1
+23552
+1

sqrt(84586075770624998147441974158189380700174460760744963832062282657, 4 = 17053939551218935.1675822943023889

do you mean this?     this is the 4th root of your gigantic number using web 2.0 calculator and the  $$\sqrt[y]{x}$$ button......   put in 'x'    push the button then enter 'y' ans   =

Apr 14, 2020
#2
+29978
0

If you expect the fourth root of your large number to be an integer you are doomed to disappointment - search "Fermat's last theorem".

Apr 14, 2020
#3
+34
0

Not exactly. Its possible to compute square of 2 (269916694664582966990754893514409**2 + 108309988975954046249057727301124**2) , but why it´s not possible to compute higher (such as 4)? It works for 2, so it must also work with 4.

Apr 14, 2020
#6
0

MathKing, you are not only doomed to disappointment, you are just doomed.

Not all is lost:  If you and Mr. BB have one of your “intellectual” conversations, then maybe Ginger will write some more hilarious satire.

Guest Apr 14, 2020
#7
+34
0

Aha, so I have totally impossible expectations.

MathKing  Apr 14, 2020
#8
0

Now, You Got It !!!!.

Guest Apr 14, 2020
#9
0

The expectation for finding an exception to Fermat’s Last Theorem is zero. The proof for that is almost 30 years old. Ginger comments on it here: https://web2.0calc.com/questions/help_79263#r8

As for the expectation that Ginger will write more satire, it probably depends on how your conversation with Mr. BB unfolds.  The one you had a year ago was new and obviously inspiring.     However, Ginger is very talented. She often can make silk purses from sow’s ears:  it’s worth a shot

Guest Apr 14, 2020
#10
0

hope ginger sees this bro 😞

Guest Apr 14, 2020
#4
0

Did you understand what Alan said about "Fermat Last Theorem" ?? Look it up and read about it !!.

Apr 14, 2020
#5
+34
0

Of course! I´d look into it...

Apr 14, 2020