the distance between (4,1) and (x,3) is the square root of 52. find the values of x
Let's make this easy on ourselves....basically, we need to solve this
(4 - x) ^2 + (3 - 1)^2 = 52 simplify
(4 - x)^2 + (2) ^2 = 52
(4 - x)^2 + 4 = 52 subtract 4 from both sisdes
(4 - x)^2 = 48
(x - 4) ^2 = 48 take both roots
x - 4 = ±√48 add 4 to both sides
x = ±√48 + 4 = ±4√ 3 + 4 = 4( 1±√ 3)
So...two "x's" make this true...
Let's make this easy on ourselves....basically, we need to solve this
(4 - x) ^2 + (3 - 1)^2 = 52 simplify
(4 - x)^2 + (2) ^2 = 52
(4 - x)^2 + 4 = 52 subtract 4 from both sisdes
(4 - x)^2 = 48
(x - 4) ^2 = 48 take both roots
x - 4 = ±√48 add 4 to both sides
x = ±√48 + 4 = ±4√ 3 + 4 = 4( 1±√ 3)
So...two "x's" make this true...