How do I change standard form into vertex forms if the equation is y=2x^2+3x-14?
+130516 y=2x^2+3x-14
First, factor out the 2
y = 2(x^2 + (3/2)x - 7)
Take 1/2 of the coefficient on x (3/4), square it =9/16.....then add and subtract it...so we have
y =2(x^2 +(3/2)x +9/16 - 7- 9/16) factor the first three terms in the parentheses
y = 2[(x + 3/4)^2 - 112/16 - 9/16] distribute the 2 across the terms in parentheses
y= 2(x + 3/4)^2 - 112/8 - 9/8 =
y= 2(x + 3/4)^2 - 121/8 .... and that's in vertex form
The vertex is (-3/4, -121/8)
+130516 y=2x^2+3x-14
First, factor out the 2
y = 2(x^2 + (3/2)x - 7)
Take 1/2 of the coefficient on x (3/4), square it =9/16.....then add and subtract it...so we have
y =2(x^2 +(3/2)x +9/16 - 7- 9/16) factor the first three terms in the parentheses
y = 2[(x + 3/4)^2 - 112/16 - 9/16] distribute the 2 across the terms in parentheses
y= 2(x + 3/4)^2 - 112/8 - 9/8 =
y= 2(x + 3/4)^2 - 121/8 .... and that's in vertex form
The vertex is (-3/4, -121/8)
