We flip a fair coin 10 times. What is the probability that we get heads in exactly 8 of the 10 flips?
We have 10C8 \(* (\frac{1}{2})^2 ≈ 0.044\)
- Daisy
It is: 10C8 x (1/2)^10 =~0.0439.........etc.
{10! / [8! * 2!]} / 2^10 =45 / 1,024 =0.0439453125.
OR: 10C2 / 2^10 =45 / 1,024 =0.0439453125.