$${\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\right)}^{{\mathtt{5}}}$$ = 12
If you are solving for x then you must isolate it onto one side.
The first step is to get rid of that pesky 5th power.
In order to do that, you must take the 5th root of both sides.
When you do this you remove the 5th power from the x side.
The next step is easy, you isolate x by adding 3 to both sides.
In the end you get x = 3 + $${\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{\mathtt{12}}}}$$
.$${\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\right)}^{{\mathtt{5}}}$$ = 12
If you are solving for x then you must isolate it onto one side.
The first step is to get rid of that pesky 5th power.
In order to do that, you must take the 5th root of both sides.
When you do this you remove the 5th power from the x side.
The next step is easy, you isolate x by adding 3 to both sides.
In the end you get x = 3 + $${\sqrt[{{\mathtt{{\mathtt{5}}}}}]{{\mathtt{12}}}}$$
