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what does 6 to the power of 7 mean

It means you will multiply 6 by itself 7 times or: 6 x 6 x 6 x 6 x 6 x 6 x 6. And it is written like this: 6^7.

The are of this square is    (2+x)   *  (2+x)   =  7

                                            4  + 4x  + x ^2   = 7       Now subtract 4 from both sides.........and.......

Close! 

The answers are yes, yes, no, yes.

FOUR of the common difference ( from term 5 to 9)   is 11  to  7     so the common d  is -1

9th is 7      16th will be   7* -1  more   = 0

Sorry, Alan, I should have specified. It is inclusive, and I'm sorry for the confusion. As for the right answer, I don't know it, but when I get it I will make sure to send you the explanation for the answer. Thank you for trying to help!

Use    tan 70 = opp/adj

tan 70 = height/12   

omg thx for the help, i couldnt be able to do it without you :)

if u r still there can u pls explain it more specifically?

Points M, N, P and are the midpoints of sides TU, US, ST and of triangle STU, respectively, and UZ is an altitude of the triangle. If angleTSU=71, angle STU=39, and angle TUS=70, then what is angle NZM+angle NPM in degrees? If you see this, please answer when you can.

Angle  NZM = 70°

Angle  NPM = 70°  

y = 1 / 6 * [730 - 9x]

There are NO integer solutions to your problem. However, you may enter any value for x from 1 and above and determine the values of x and y that way.

p = 1/256.  q = 1 - 1/256 = 255/256

prob q occurs 256 times on the trot = q²⁵⁶ 

Let what Rahim had to start with =R
Brian had =3R

3R -  158 =R + 42, solve for R
R = $100 - Amount that Rahim started with.
$100 x 3 =$300 - Amount that Brian started with.

Each pair intersect in 2 points.

The first circle intersects 9 others.

The 2nd circle intersects 8 others (not counting its intersections with the first circle)

The 3rd circle intersects 7 others (not counting its intersections with the first two)

....

The 9th circle intersects 1 other (not counting ...etc)

The 10th circle already intersects all the others.

Hence number of intersection points = 2*(9+8+7+6+5+4+3+2+1) = 2*45 = 90.

Find a monic quadratic polynomial f(x)  such that the remainder when f(x) is divided by x-1 is 2
and the remainder when f(x) is divided by x-3 is 4.

\(\begin{array}{|rcll|} \hline \mathbf{f(x)} &=& \mathbf{q_1(x)(x-1) + 2} \quad &| \quad x = 1 \\ f(1) &=& q_1(x)*0 + 2 \\ \mathbf{f(1)} &=& \mathbf{2} \\\\ \mathbf{f(x)} &=& \mathbf{ q_2(x)(x-3) + 4 } \quad &| \quad x = 3 \\ f(3) &=& q_2(x)*0 + 4 \\ \mathbf{f(3)} &=& \mathbf{4} \\ \hline \end{array}\)

Monic quadratic polynomial \(f(x) = x^2+ax+b\)

\(\begin{array}{|rcll|} \hline \mathbf{f(x)} &=& \mathbf{x^2+ax+b} \\\\ f(1) &=& 1^2+a*1 + b \quad & | \quad f(1) = 2 \\ 2 &=& 1+a+b \\ 1 &=& a+b \\ \mathbf{b} &=& \mathbf{1-a} \\\\ f(3) &=& 3^2+a*3 + b \quad & | \quad f(3) = 4 \\ 4 &=& 9+3a + b \quad &| \quad b=1-a \\ 4 &=& 9+3a + 1-a \\ 4 &=& 10+2a \\ -6 &=& 2a \\ a &=& -\dfrac{6}{2} \\ \mathbf{a} &=& \mathbf{-3} \\\\ \mathbf{b} &=& \mathbf{1-a} \\ b &=& 1-(-3) \\ b &=& 1+3 \\ \mathbf{b} &=& \mathbf{4} \\ \hline \end{array} \)

\(\mathbf{f(x) = x^2-3x+4 }\)

If they intersect at the point (x, y, z) then you have:

7 - 2x = 8 + x

-3 + 5y = -1 - 4y

1 + z = -1

I'm sure you can take it from here.

A store sells white scarves and red scarves . A white scarf is $3 and a red scarf is $5. One day the store sold 12 scarves for $50. What is the total number of scarves sold on that day?

y = x^5-1   /3          find the inverse function

x =  y^5-1   /3

(3x +1)^1/5 =y         this is f^-1

(3(-31/96)+1 )^1/5 =y

y = 1/2

This situation forms a right triangle......the line of sight to the nest is the hypotenuse and one leg os 10 feet while the other leg is the height of the nest.

tan 55^o = opp/adj

tan 55   = height/10 ft

1.428  =  height / 10             solve for height.

Yvette has six beads that she is going to assemble into a bracelet. Two of the six beads have the same color R, and the remaining four all have different colors BGYP. How many different ways can Yvette assemble her bracelet? (Two bracelets are considered identical if one can be rotated and/or reflected to obtain the other.)

Im going to let the B mark the beginning. Now I have 5 more beads and 2 are the same.  So I think that is 5!/2! = 60 ways

Lets try it a different way

Let a red mark the beginning then I have 5!/2 which will still equals 60

So I think the answer is 60.  Oh dear I have accounted for rotation but not for reflection.

I did work out how to deal with reflection before but I have forgotten.....

So the answer is less than 60. 

I think Just divide by 2

So my best guess is that the answer is 30

Let us know when you find out the given answer.

As follows:

I'll let you take it from here.

a=1; b=1;c=1;d=a*100 +b*127; if(d<=500, goto5, goto6);print a, b, c, d; a++;if(a<10, goto3, 0);a=1;b++;if(b<10, goto3, discard=0; a=1;b=1;c++;if(c<10, goto3, 0)

OUTPUT:

a          b         c

1         1        227
2         1        327
3         1        427
1         2        354
2         2        454
1         3        481

The word "or" is ambiguous. 

It can mean inclusive or (one or the other or both), which is what I took it to mean.

It can mean exclusive or (one or the other but not both).

If exclusive or was meant here then the probability becomes:

p(at least 2 white)*(1-p(red)) + p(red)*(1-p(at least two white))   so:   (1/15)*(1-1/10) + (1/10)*(1-1/15) = 23/150

(The above numerical value assumes I've calculated the individual probabilities correctly!).