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first you have to make division, just after that multiplication. that why it is 9

GuestFeb 17, 2013

Feb 16, 2013

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6/2(1+2)....

As written, it is ambiguous due to the improper use of parentheses. It could be interpreted as either (6/2)*(1+2) = 9 or 6/[2*(1+2)] = 1. As written, a calculator is likely to interpret it as (6/2)*(1+2), since the lack of parentheses generally indicates only the immediate following term is assumed to be in the denominator. This isn't a PEMDAS issue (i.e., order of operations) issue so much as a poor notation issue.

GuestFeb 16, 2013

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1*5^2+3*5+2*5^0=1*25+3*5+2*1=25+15+2=42 maybe?

GuestFeb 16, 2013

Feb 15, 2013

+3146

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[input]2x^2=100[/input]

adminFeb 15, 2013

Feb 13, 2013

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GuestFeb 13, 2013

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Which weight has the ball?

GuestFeb 13, 2013

Feb 12, 2013

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GuestFeb 12, 2013

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isnt it PE M/D A/S

GuestFeb 12, 2013

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GuestFeb 12, 2013

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GuestFeb 12, 2013

Feb 11, 2013

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PEMDAS Parentheses, Exponent, Multiply, Divide, Add, Subtract
6/2(1+2) First Parentheses = 6/2(3)
6/2(3) No exponents so multiply = 6/6
6/6 Divide =1
1 is the answer

GuestFeb 11, 2013

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guest:
what is1+3/9*3456?

It depends on whether your problem is (1 + 3/9)*3459 or 1 + (3/9 *3456). The first one is 4612, and the second one is 1153. So, you have to use the order of operations (i.e., parenthesis) correctly as the answers are different for each.

GuestFeb 11, 2013

Feb 10, 2013

+3146

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[input]x^4+4=0[/input]

adminFeb 10, 2013

Feb 7, 2013

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sorry about this, but if u see properly, u might have noticed that I interchanged the values when I substituted in the formula, i.e I took "y2-y1" instead of "y1-y2". But, as u may know, when u reverse the subtraction of 2 numbers, u just get the negative answer, the absolute number isn't changed. So, "x-y" = -"y-x". But, in the formula, these terms are squared, and whether they are negative or positive, their squares are the same.

GuestFeb 7, 2013

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In co-ordinate geometry, there is this "distance formula" that goes " Distance between P(x1,y1) and Q(x2,y2) on a 2-dimensional plane is given by sqrt[(x1-x2)^2 + (y1-y2)^2]"
What that means, is:
Let's call the 1st point "P".It has the co-ordinates (11,-4) .These are the values of "x1, and y1"
Let the 2nd point be "Q".It has co-ordinates (11,4), which we can take as "x2 and y2"
Applying distance formula,

Distance = sqrt[(11-11)^2 + (4-(-4))^2]
=sqrt[0^2 + (4 + 4)^2]
=sqrt[8^2]
=8 [sqrt cancels the "square" of 8 squared]

You can do the next one..
hope this helped

GuestFeb 7, 2013

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4 divided by 12 , or 4/12 reduces to 1/3.Both one and three are odd, and therefore both their product and quotient will be "odd"...

GuestFeb 7, 2013

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Well, u can tread the "sqrt(2)" as a variable, like "x"
so 4*sqrt(2) +7*sqrt(2) -3*sqrt(2) = sqrt(2)*(4 + 7 - 3) [you take sqrt(2) as a common coefficient, or variable, or factor w/e u wanna call it]
= sqrt(2)*(8)
=8*sqrt(2)
Normally, for class purposes, we stop there, and are not required to bother further, but if u use a calculator, then it gives 11.3137....
If u already knew this, then I'm sorry for wasting time lol

GuestFeb 7, 2013

Feb 5, 2013

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Sorry my mistake did it wrong ok so wat u do is subtract the 3 making it -y=x-3 but u cant have a negative y so you divide everything by -1 so it should end up being y=-x+3

GuestFeb 5, 2013

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you subtract x making it -y=-x+3 then divide everything by -1 making it y=x-3.After that you put it in a scientific calculator and i hope you can go of from here

GuestFeb 5, 2013

Feb 3, 2013

+3146

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[input]log(0.06)[/input]

log( u/v ) = log( u ) - log( v )

0.06 = 6 / 100

log( 0.06 ) = log( 6 / 100 ) = log( 6 ) - log( 100 ) = log(6) - 2

[input]log(6) - 2[/input]

adminFeb 3, 2013

Feb 1, 2013

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GuestFeb 1, 2013

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4x-6>-10
[size=85]+6 +6[/size]
4x>-4
[size=85]/4 /4[/size]
x>-1

GuestFeb 1, 2013

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GuestFeb 1, 2013

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soh cah toa. Sin is opp./hypotenuse. CoSin is adjacent/hypotenuse. Tan is opp./adjacent. use these

GuestFeb 1, 2013

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GuestFeb 1, 2013

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