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Venn diagram:

(a)  P(4  red  balls)  =  C(10, 4) (20/50) (19/49)(18/48)(17/47)(30/46)(29/45)(28/44)(27/43)(26/42)(25/41)  =

82195425

__________   ≈      .28   =   28%

293493662

Is this question from aops?

Similar      see if you can do the same with the numbers you have.....

https://web2.0calc.com/questions/help-please_25780

Plot all of those points......   then bring the graph back here and we can help you further......    

I thought we already decided that f<= 11.25 lb   Why is this posted THREE times????  

a + b = 39 + c

c = a - 23

a + b + c = 211     but a+b = 39 + c

39 + c  + c  = 211

c = 86      = a - 23               so a = 109      then b = 16

725 tix total

x  = adult                 revenue from adult tix = $2.50 x

725-x = child           revenue from child tix = $ 1.00 (725-x)       revenues summed = $ 1325

2.50 x  + 1.00 (725-x)  = 1325      solve for 'x' the # adult tix.......then child tix = 725-x     

https://web2.0calc.com/questions/algebra-help-pls_1

https://web2.0calc.com/questions/math-question-help_10

L

C = 1/2 L

M = 3 (1/2L)      this is all given in the Q     they sum to 60

L     +   1/2 L     + 3 (1/3L)   = 60

                                   Solve for L  then C = 1/2 L

William, you are old enough to b**w your nose without having mommy hold the booger rag. Just Google it; there are many pages that will show you how the Sine rule works. 

Also, STOP using “help” as a title to your questions. We know you need help else you’d not be asking.

*was

Hi Madyl,

I like the big picture, and the title.

I'm not good on ellipses though.......

Just use the sine rule.

To have removed at most 2 pennies out of 4 coins, you could have either selected 4 nickels, 3 nickels and 1 penny, or 2 nickels and 2 pennies.

There is only one way to select 4 nickels:  6/11 x 5/10 x 4/9 x 3/8  =  1/22

There are four ways to select 3 nickels and 1 penny; each way is:  6/11 x 5/10 x 4/9 x 5/8  =  1/66

     4 x 1/66  =  2/33

There are six ways to select 2 nickels and 2 pennies; each way is:  6/11 x 5/10 x 5/9 x 4/8  =   5/66

     6 x 5/66  =  5/11

Adding these probabilities:  1/22 + 2/33 + 5/11  =  37/66

r² = 625   

The first card can be any card:    52/52

The next card can be any of the twelve cards that are of the same suit as the first card:  12/51

Probability  =  52/52 x 12/51  =  4/17