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I did that because I didn't understand the question myself and assumed that someone will tell me what is missing, and will tell me what. The first person didn't, so I just said that is was incomplete. I didn't need someone to tell me to behave myself! Also, you are telling me to apologize? You should apologize to me first, and then I will think about it.

I recommend creating an account. I coudn't use it, and after so many tries, I created an account. The weird popups went away after creating an account! You should try it. 

I think this is supposed to be a logistics  growth/decay  equation.....we  have   that

                           12

f(x)   =           _________ 

                        a + e^(kx)

We know that   f(0)  = 2      this makes   e^(kx)   =  e^(k*0)  =  1

So

                  12

  2 =        _____

                 a + 1

Means that   a  =   5

And   f(1)  =  1/2      ....so.......

                            12

1/2    =            _________           rearrange as  

                         5 + e^(k)

5 + e^(k)  =  12   /   (1/2)

5  +  e^k   =   24        subtract    5 from both sides

e^k =    19         

This   implies  that     

Ln e^k  = Ln 19

k * Ln e   =   Ln 19

k * (1)  = Ln 19

k = Ln 19

f(3)   =           12   /  [ 5  + e^(3 * Ln 19) ]   =      1  / 572

Here's the graph : https://www.desmos.com/calculator/9lngaoxfod

I think it is B too maybe. If you get it wrong don't blame me!!!

Thanks, EP   !!!!!

Note  that if we  multiply  g(x)  by  -(1/2)  we get   -x^4 + 3x^2 -x + 1/2

Adding this  to  f(x) produces  -x + 5/2

So....the  smallest  possible  degree of  f(x) + b * g(x)   =    1

Area  =  W * L

160  =  W ( W + 6)      simplify

!60    =  W^2  + 6W     rearrange as

W^2  + 6W  - 160  =  0        factor

(W  + 16) ( W  - 10)  =  0  

Only  the  second factor produces  what we want   W -  10   =   0  ⇒   W   = 10  yards

Chill bro WE ARE MORE THAN JUST BAGS OF FLESH

life is meaningless we are all bags of flesh meant to die edgy bags of flesh like me are so much cooler than than normal bags of flesh hahahahhahahhahahahhah

Strong work, Chris !    ouch !

1.109 x  = 277

x = 249.77   10 years ago

277 = 249.77 e^k(10)

^{k = .0103458}

400 = 249.77 e^.0103458t

     ^{yields t = 45.51 years    from the time the population was   249.77  (ten years ago)      35.51 years from population of 277 million (presently)}

Hey mharrigan! In this problem, we'll make use of a useful log identity. 

\(\log_{a}b + \log_ac = \log_{a}bc\)

Given that these two logs have the same base.

As such, since we have:

\(\log_au + \log_av\), we can rewrite this to equal:

\(\log_au + \log_av = \log_a{uv}\)

This is where the question becomes kind of murky. The problem itself never says what "true or false" means in the context of the problem. Does it mean for all u and v, or just find one u and v so that it satisfies that requirement? Meaning that for all we know, uv could equal u + v(we don't know, it never says?). Contrary to Cal's answer, if the problem asked you to find one such case so that this expression holds true, then the answer would be true(we can have 2 and 2, which would work). However, if it was in general, then it would be definitely false. 

OwO i can feel the catness already 

a)   Since the population grew by 10.9% in the last 10 years......we have that

 A₀ * ( 1.109)  =  277    divide both sides  by  (1.109)

A₀  =   277 / (1.109)   ≈  250

b ) So   to find the annual growth  rate  we  can solve  for  this

277  = 250e ^(k * 10)      divide both sides  by  250

277/250   e ^(10k)       take the Ln of both sides

Ln  (277/250)  = Ln e^(10k)      and we can write

Ln (277/250)  = 10k * Ln e           Ln e   =1

LN (277/250)  / 10   =  k  ≈ .01025   =  annual  growth rate of ≈ 1.025 %

c)   400  = 277 e ^(.01025 * t)        divide both sides by 277

400 / 277  = e^(.01025 * t)       take the Ln again

Ln (400 /277)  = .01025 t     divide  both sides  by   01025

Ln (400/277) / .01025  = t ≈ 35.8   years from the first year =  25.8 years from now 

U_w^U    tank Q

nicesu nicesu

wish you more awesome days

Thanks for your thx!

  !

My day= awesome!

Second question: x=algebra

                             y=geometry

                             3x=calculus (LOL)