Please tell me you're not trolling
And anyway, the answer wouldn't be 0. It would be 000. Know the difference.
I know. It's just that it will be lots of work.
Aw, but 0 can be very large in a world of negative numbers. I guess we live in a positive world then. Why am I having senseless thoughts.
The so on is meant to say that this continues until you get down to the last room.
You're reposting a problem. Again. Did you not get it last time? I'm pretty sure you said you did.
There are ten rooms
Read the problem: it says there are a very large number.
This sounds like the meme where the guy asks if n is a lot.
Thank you, CPhill !
That is true! Technically, if there are 0 blocks, the blocks can be evenly distributed
First room: \(\binom{20}{2}\)
Second room: \(\binom{18}{2}\)
And so on. Use multiplication I think. Someone check my work because knowing these types of problems there's usually a catch or my method is completely wrong.
Aww... I thought I was getting somewhere...
Thx, Cal !!!!!
Or don't be an idiot like me and use modulo to find it easily. Your call.
There aren't that many four digit numbers divisible by 625. Calculator bash time. Due to parity, only check 625 x odd numbers.
Average =
[ 2*40 + 3*50 + 10*60 + 25*70 + 35*80 + 18*90 + 7*100 ] / 100 =
[7700 ] / 100
77
CORRECTED
Cal just showed my the answer, lol
After that, there aren't many left. Time to use some more logic, I presume, but I'm lazy and won't do it.
Tricky problems always require some logic. I think we can rule out 1, 2, 3, 4, 5, 7, and 8 due to the parameters put forth in the problem.
Check this:
https://artofproblemsolving.com/wiki/index.php/2013_AIME_I_Problems/Problem_11
The answer is D. hormone balance.
Vectors that will work are [1,2], [2,4], [3,6].
\(N(N-1)\)
one must be divisible by 625 and the other must be divisible by 16. This might lead us anywhere?