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529 tourists....not sure how I got that answer.....I'll post method if I can 'figure it'

Do you mean to leave the value of BC to be blank?

Label the triangle as traingle(ABC), with A = left-bottom corner, B = right-bottom corner, and C = top corner.

Label the square as square(DEFG) with D = left-bottom corner, E = right-bottom corner, F on BC, and G on AC.

The bottom side of the triangle is now ADEB.

Let AD = 1.

Since angle(A) = 60^o and triangle(ADG) is a right triangle, AG = 2 and DG = sqrt(3).

Since DG = sqrt(3), DE, EF, and FG are all equal to sqrt(3).

This means that the square DEFG has an area of  sqrt(3) · sqrt(3)  =  3.

The bottom of the triangle, ADEB = AD + DE + EB.

AD = 1, DE = sqrt(3), and EB = 1, so ADEB = 2 + sqrt(3).

The formula for the area of an equilateral triangle is  A  =  sqrt(3) · s² / 3

--->   A  =  sqrt(3) · [ 2 + sqrt(3) ]² / 3  =  [ 7·sqrt(3) + 12 ] / 4

The ratio of the area of the square to the area of the triangle is:  3 : [ 7·sqrt(3) + 12 ] / 4

I think what guest meant was

Let \(f(x)=\left\lfloor\left(-\frac58\right)^x\right\rfloor\) be a function that is defined for all values of \(x\) in \([0,\infty)\) such that \(f(x)\) is a real number. How many distinct values exist in the range of \(f(x)\)

6 dollars does not seem like a lot. 

*sets up paypal acct*

here!

lol

n = 6

think you might need to reformat that...

Sin a = 2 sin(90-a)

sina= 2cosa

sina/cosa = tana = 2

arctan(2)= 63.43^o=a.      b= 90-a==26.56^o

In 24 s. Tasha completes. 24/56 lap= .428. Lap.      Daniella completes  1- .428 lap in that 24 s

24/ (1-.428) = 42 s per lap

Net 1200 - 800= 400 East.   And

900-700= 200 feet north

sqrt(400^2 + 200^2) = ......... ft from start point

(9, 6, 5, 3).

9+6+5+3 = 23.

The smallest is: 1,358 =1 + 3 + 5 + 8 = 17
The largest is:    8,531 = 8 + 5 + 3 + 1 = 17
Note: it is the same number reversed. if you wish a different number, then 6,541 would be the next largest such number.

Using the shoelace theorem, we find that the answer is 15.

Using the quadratic formula, we find that the roots are -3+4i and -3-4i.

(m, n) = (9, 4).

I believe StackOverflow would be much more useful.

I don't do python normally, usually Java, C/C++, HTML, stuff like that.

I never studied the Golden Ratio so idk how it works but you might want something like this

for i in range(1,20):

(content)

Idk.

(a + 1/b)(b + 1/c)(c + 1/a)

=  [ (a + 1/b)(b + 1/c) ] (c + 1/a)

=  [ ab + a/c + 1 + 1/bc ] (c + 1/a)

=  abc + b + a + 1/c + c + 1/a + 1/b + 1/abc

=  abc + (a + b + c) + (1/a + 1/b + 1/c) + 1/abc

(1 + 1/a)(1 + 1/b)(1 + 1/c)

=  [ (1 + 1/a)(1 + 1/b) ]·(1 + 1/c)

=  [ 1 + 1/b + 1/a + 1/ab ]·(1 + 1/c)

=  1 + 1/c + 1/b + 1/bc + 1/a + 1/ac + 1/ab + 1/abc

=  1 + (1/a + 1/b + 1/c) + (1/ab + 1/ac + 1/bc) + 1/abc

Setting these two equal to each other:

abc + (a + b + c) + (1/a + 1/b + 1/c) + 1/abc  =  1 + (1/a + 1/b + 1/c) + (1/ab + 1/ac + 1/bc) + 1/abc

Subtracting like terms:

abc + (a + b + c)  =  1 + (1/ab + 1/ac + 1/bc)

Rewriting:

abc + (a + b + c)  =  1 + (c/abc + b/abc + a/abc)

Factoring:

abc + (a + b + c)  =  1 + (a + b + c)/abc

Since abc = 13:

13 + (a + b + c)  =  1 + (a + b + c)/13

Subtracting:

12 + (a + b + c)  =  (a + b + c)/13

Multiplying both sides by 13:

156 + 13(a + b + c)  =  (a + b + c)

Subtracting (a + b + c) from both sides:

156 + 12(a + b + c)  =  0

Subtracting 156 from both sides:

12(a + b + c)  =  -156

Dividing:

a + b + c  =  -13

The slope of the line is    (y1-y2)/ (x1-x2) = (0-4)/(9--3) = -4/12 = -1/3

The slope between   a,1    and either of the other two poins must equal  - 1/3

(0-1)/(9-a) = - 1/3

-1/(9-a) = -1/3

-1/(-1/3) = 9-a

3 = 9-a        a = 6

 H   red      H  blue      H green    H black      H  yellow       H pink

 T   red       T blue ..............etc..........................................T pink

Yep! I submitted it and it was correct

wait so it's 2 times the square root of 10

Use Quadratic Formula

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)       a = 1   b = 6  c = 25         Plug and chug....

I figured that out already...

Drop a plumbline from the upper left corner tot the '8' line ....this creates a right triangle with one leg = 3   one leg = missing side length and hypotenuse = 7

The use Pythagorean theorem to solve for the missing leg length.....