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x :  from 6 to -6  is   -12     3/4 * -12 = -9     added to 6  is       -3

y:   from -6 to -2  is  +4      3/4 * 4 = 3          added to -6 is     -3

Use cos rule

e² = 10²  + 7²  - 2 (10)(7) cos 34    solve for e

  1000* (1 + .10)3 -1000  = interest in 3 yrs

50 m/h  x  .5 hr  =  25 miles

60 m/h  x 1.5 hr = 90 miles

total miles/totaltime =  115 m/ 2 hr = 57.5 m/hr avg

This is how that inscribed triangle actually looks.

Scale 1:1  

The intersection is (a,b) = (5,-3), so a + b = 5 + (-3) = 2.

The quadratic is (x - 3)(x - 2) = x^2 - 5x + 6, so b + c = (-5) + 6 = 1.

The smallest possible value of x + y = 4 + 405 = 409.

Using similar triangles, PQ = 10*sqrt(2).

The maximium number of distinct integer solutions is 5.

Using similar triangles, YZ = 47/5.

The largest negative integer is x = -13.

57 is to 63     as    CG is to 21

57/63 = CG/21       Take it from here ! 

Using similar triangles, PQ = 5*sqrt(3).

536 ft   is to 336  ft   as  AB is to 210

536/336 = AB / 210  

AB = 536/336   *  210 = 335  ft     Now you should be able to determine  AC

Reflection matrix for y = 1/2*x + 5 applied to (6,2):

\(\begin{pmatrix} 3/5 & 4/5 \\ 4/5 & -3/5 \end{pmatrix} \begin{pmatrix} 6 \\ 2 \end{pmatrix} = \begin{pmatrix} 26/5 \\ 18/5 \end{pmatrix}\)

So the relfection is B = (26/5,18/5).

1. The constant term is -432.

2. The cosntant term is 15.

BK = 11/2 and LC = 14.

Diagram: