On average, 1 out of 10 times you will draw the AwesomeBall (and this wins all by itself so we don't care what the other balls are) for a winning probability of 0.10.
Now, for the 9 out of ten times that you do not draw the AwesomeBall:
We will have to get a losing blue ball, I'll call that B (and the probability of getting that losing ball is 0.90).
We can win by getting two or more of the white balls. I'll classify a winning white ball (whose probability is 1/10 = 010)
as W and a losing white ball as L (whose probability is 9/10 = 0.90).
So, we can still win if we have this:
B x W x W x W = (0.90) x (0.10) x (0.10) x (0.10) = 0.0009
B x W x W x L = (0.90) x (0.10) x (0.90) x (0.10) = 0.0081
B x W x L x W = ...
B x L x W x W = ...
Since these are independent, add the above 5 results together, to get 47/200.