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Thank you for answering despite me not telling what degree it is. I appreciate it very much! 

180-79=101

36+101+(3x-40)=180

137+(3x-40)=180

3x-40=43

3x=83

x=83/3

A. 83/3

:)

what requires an input of thermal energy?    

Boiling a half-dozen eggs. 

Soldering a wire to a post.  

Lighting the fireplace.  

google translates this as  "I PLAYED DICE WITH MY FRIEND GAEL, I THROWN MY 12-SIDED DICE AND I GOT A 10, AND HE THROWN HIS 12-SIDED DICE BUT THE NUMBER WAS NOT SEEN, WHAT ARE MY CHANCES THAT HIS NUMBER IS GREATER THAN OWN? {THE VERTICAL LINE WITH NUMBERS IS MY DICE AND THE HORIZONTAL LINE WITH NUMBERS IS GAEL'S DICE}"  

Triangle BCG is an isosceles right triangle.

BG and CG are the radii of a circle G.

(BC)² = 2r²            BC = r√2

*This is a problem on the 2021 amc 10 b!! Please do not cheat!*

*Do NOT answer this question yet! It's a problem on the 2021 amc 10 B!!*

Is this a question on the AMC 12?

plz dont cheat it does not benefit you.

Is there a plus between the 2 polynomials. 

If there is then here is the solution,

If you expand the expression you get,

[x^2 -4x +4] + [x^3 +6x^2 + 12x + 8]

you can simplify this even more...

x^3 + 7x^2 +8x + 12

you basically multiply all of the coefficents of x so....

1 x 7 x 8 = 56

you dont mulitply eight becasue it is not a coefficient of x.

Is there a solution? If you are given the answer, there should be a solution to go along with it.

LOL!!!....cheating is bad.....lazy cheating is worse   !!!!

We're  asking  at  what  x  value does  the  graph  reach 4  on y

This  is at  x   =  3

I think, that in sailing, a  bearing of  0°  is true North  and  the  bearing angle is  measured  clock-wise  from  this position

A bearing of 293° ( trigonometrically  speaking)  corresponds   to   an angle of 360  - 293  -90   =157°

{Note  that a bearing of 270°  =  180°  in  trigonometric terms.....so  180  - 23 =  157° }

In 3 1/2 hours....the  ship   has traveled 63 miles

So.....its   position in the  coordinate plane =  (  63 cos 157° . 63 sin 157°) = (-58  , 24.6)

So   it is   58  miles west   and  24.6 miles north of its  original position 

See the image  here , lovesosa12  :

A is the starting point   and B is the  ending point

@CPhill that's because it's from the AMC and he couldn't even bother to write down the letters

Hey there, Guest!

As you probably already know, thermal energy is heat.

Some common things that use thermal energy are: When we drive cars and they burn fuel or a coffee machine!

Hope this helped!

( ﾟдﾟ)つ Bye

Thank you so much, saved me so much hassle!

Do not cheat on the AMC 12.

Missing  some  numbers  ????

First one :

The blue  graph  is the  red graph shifted to  the  left by 2 units

Its equation  is  y  = f ( x + 2)

The second one   is the red graph shifted up 3 units

Its equation is  y  = f(x)  + 3

Let x  be  the number of fruit pies  that Mr. Sanchez's class sold

Let 79 - x  be   the  bottles of   fruit juice that Mr. Kelly's class sold

So we  have

1.65x   + 1.36 ( 79  - x)  =  118.17      simplify

1.65x  + 107.44 - 1.36x  = 118.17

1.65x - 1.36x =   118.17 -  107.44

.29x  =  10.73      divide both sides by .29

x =  37    fruit pies sold

79 - 37 =  42  bottles of  fruit juice  sold

1.65 * 37  = $61.05  =  what Mr. Sanchez's class made

118.17 - 61.05  = $57.12  = what Mr. Kelly's class made 

61.05 -  57.12  =   $3.93    more

I saw that you posted a question, but you just edited it out. What was the question?

dont cheat bud

Please don't cheat on the AMC

Let x  be  the number of  seconds  that have elapsed

Since    at  x  = 0 the cannon ball was 2 ft off the ground, then  c =  2

And we  have  that

a(.1)^2   + b(.1)  +  2  = 33    ⇒   .01a + .1b =  31   (1)

And

a(.2)^2 + b(.2) + 2 =  22   ⇒    .04a + .2b =  20     (2)

Multiply (1)  by -2  ⇒   -02a - .2b   =  -62

Add this to (2)

.02a  = -42       divide both sides  by   .02

a= -2100

And  using any equation , we  can  find b  as

.04 (-2100) + .2b   =  20

-84 +  .2b  = 20

.2b  =  20 + 84

.2b  = 104       divide both sides by .2

b = 520

a = -2100

b = 520

c = 2

See the graph, here :  https://www.desmos.com/calculator/sjtjtjnlwc

Second part  .....I think they mean the Quadratic Formula....not the Pythagorean Theorem

Time  to hit  the  ground  =

(-520  ± sqrt  ( 520^2 - 4 (-2100) (2) ) )  / ( 2 * -2100)  =

(-520 ± sqrt (287200) ) /( -4200)   =

Take the  negative sqrt

(-520   -  20sqrt (718) ) / (-4200)   ≈  .25  seconds