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In each hour between 12:00 pm and 12:00 am [excluding 3:00 pm to 3:59 pm], the minute hand shows: 16 "threes" x 11 =176 times - repeats counted.

Between 3:00 pm and 3:59 pm, the hour hand + the minute hand show: 76  "threes" - repeats counted.

Total number of "threes" that appear between 12 pm and 12 am =176 + 76 =252 "threes" - with all repeats such as 1:33, 3:03, 3:33....etc. counted.

a + m = 3 + 12 = 15.

find f(x+h) and f(x) then plug values into formula

2x+h−6

find f(x+h) and f(x) then plug values into formula. 

√x+h−4−√x−4

        h

I graphed it, and found 3 real solutions.

The magnitude of an angle is the amount of rotation through which one of the arms must be rotated about the vertex to bring it to the position of the other arm.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The magnitude of angle ABC is 150 degrees.

The answer is 2*2*2 = 8.

There are 25 integers that work.

18 (sqrt 4*2)   - 8 sqrt 2 = sqrt n

36 sqrt 2 - 8 sqrt 2  = sqrt n

28 sqrt 2   = sqrt n      square both sides

n = 1568

Not so...

First, we calculate the value of x

(6x - 11) + 81 + (x + 5) = 180

x = 15

(4y - 18) + (6x - 11) + (y + 14) = 180

(4y - 18) + (6*15 - 11) + (y + 14) = 180

y = 21

x = -1/2  is the only one

There are 7 isosceles triangles:

1/  ABC

2/  ABD

3/  BCD

4/  BDE

5/  CDE

6/  DEF

7/  CEF

Sorry   TA...the question states that the account is compounded annually.....so it is not simple interest.....

(-3.8, 4.2), (-3.8, -1.8)   Probably NOT a function as there are two values of y for x = -3.8

900 divided 225= 4²       4^{2 x} 25=400       0.4x10^{4 at 900m}

Hey there, Guest!

So if Lucas gets 3% of $1500 each year, then he's earning $45 a year.

So, 45*5=$225.

Then, we do the simple equations part:

    $1500

+  $ 225

---------------

   $1725

So, after 5 years, Lucas would have $1725 in his savings account.

Hope this helped!

( ﾟдﾟ)つ Bye

Pick an easy number ...10 ml of solution to start

salt in starting solution = salt in final solution

.04 (10) = .06 ( 10-x)        x is the amount to remove from the 10 ml

.4 = .6 - .06x

-.2 = - .06x

x = 3.33                        remove   3.333 ml from every 10 ml starting amount    3.3333/10 = 33 1/3 %

c.)   Similar to b    but now you have 9 first choices   

               and either 9 (if you can choose the same dish twice) or 8 second choices (if you cannot choose the same dish twice)......

d.)   similar again   14 first choices and either   14 (if you can choose the same dish twice) or 13 second choices  .......

DO you know how to solve simutaneous equations in two variables via substitution or elimination?

3L + 5S =133

12L + 2S = 253     Multiply top equation by -4   then add it to the second equation ....this will allow you to solve for S

                                    use this value of S in oneof the equations to solve for L

Whatdo you mean by or? So what are the answers?

It is 27500

b.)    IF you can choose two fo the SAME sweet dishes   

              first choice  5  possibles

              second choice 5 possible      5* 5 = 25 combo plates sweet

        if you CANNOT choose the same dish twice

            first choice 5 possibles

             second choice 4 possibles      5*4 =20 sweet combo plates

c.)   Similar to b    but now you have 9 first choices    and either 9 or 8 second choices......

d.)   similar again   14 first choices and either   14 or 13 second choices  .......

Thanks!!!

Just put x = 3   into the equation to compute the value

   then add the value found when you put  x = -3 into the equation.....

12 (3)⁹  + 3       +    12 (-3)⁹   -3 = 0

f(3)) = 12(3)^9+3

f(-3) = 12(-3)^9-3

Notice how the 2 answers are negative of each other. -a + a = 0

So our answer is 0.

=^._.^=