Nice solution guest and logarhythm!
Here's an alternate solution:
We need to find the coefficients of x^2, x, and constants of both (1+2x)5 and (2−x)6.
To do that, use the binomial theorem (explained here: https://www.mathsisfun.com/algebra/binomial-theorem.html )
Knowing that, the constant, x, and x^2 coefficients of (1+2x)5 are 5 choose 0 = 1 , 5 choose 1 * 2 = 10, and 5 choose 2 * 2^2 = 40, respectively, and the constant, x, and x^2 coefficients of (2−x)6 are 6 choose 0 * 2^6 = 64, 6 choose 1 * -1 * 2^5 = -192, and 6 choose 2 * 2^4 = 240, respectively.
The x^2 term of the product of the 2 expressions will happen when an x term of one expression is multiplied by the x term in the other expression, or when the x^2 term in one expression is multiplied by a constant term in the other expression.
That is equal to 64⋅40+−192⋅10+240⋅1=880
.