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Each triangle is 7.5*16=120    <======= slight mistake here Varxaax       We all have hiccups!

Base is   13 x 13 = 169 ft ^2

each of the triangles   is   1/2 b h =  1/2  13 x 16 = 104 ft²      there is 4 of them    104 *4 = 416 ft²

416 + 169 =  585 ft²

He needs to average   10 km / hour   (his goal)   

   he has run 2 km  @ 12 km/ hr       2km / 12 km/hr = 1 / 6  hr   (10 minutes)

          he has to run the remaining   8 km   in 50 minutes   (5/6 hr)       8 km/ (5/6 hr ) =  48/5  km/ hr     =  9.6   km / hr

13² is 169

Each triangle is 7.5*16=120

120*4=480

480+169=649

Yay!

EDIT: did my math wrong lul, try the one either below or above mine

The square prism base is      4 x 4   x   5 ²          ( 5 sides)

Need to find the HEIGHT of the triangles

   Pythag therom    (drop a bisector from the tip the the middle of the sidelength to form a rt triangle)  )

      2 ^2 + h^2 = 6^2

        h^2 = 32

         h = sqrt 32

FOUR triangles   base = 4    height = sqrt 32     area = 1/2 b h

     4 *      1/2  4 * sqrt 32   = 8 sqrt 32 = 45.25   cm²

Now add the reds to finish.......

From Home to the post office = 7/8 + 5/6 mile = 41/24 mile

(41/ 24 + x ) mile   *    18 min/mile   =   42 minutes         x = distance from PO to Freind's crib

      x =    42 /18   - 41/24   =   .625   miles       ( 5/8 mile)

I am confused what the answer should be and i typed 4.8 and it was wrong.

At  12K per hour....it takes him  5 min per each kilometer  (do you see this  ???  )

(Think about it.....there are 12 equal parts  in one hour  ...so...he runs 2 km in 10 min )

So....he   has to cover   10  - 2    =  8  kilometers in 50 remaining  minutes =  5/6 hr

So

Rate    = Distance /  Time

Rate  =  8  /( 5/6)   =    8  * (6/5)   =  48/5 km /hr    =  9.6 km/ hr    for the rest of the race

YOU paint  1 fence / 2hr    =   .5 f/hr

Bruh paints  1 fence/3 hr   = .333 f/hr

    when you are finished in 2 hours he still has 1/3 to go

        1/3 fenc / ( .5 f/hr + .333 f/ hr) =    1/3 / .833 = .40 hr        .40  * 60 min/hr = 24 minutes for you both to finish

For AVERAGE SPEED calculations , you have to consider TIME

   because    km run / TIME = average 'speed'

He needs to average   6 km / hour   (his goal)   

   he has run 2 km  @ 12 km/ hr       2km / 12 km/hr = 1 / 6  hr   (10 minutes)

          he has to run the remaining   8 km   in 50 minutes   (5/6 hr)       8 km/ (5/6 hr ) =  48/5  km/ hr     =  9.6   km / hr

EGAD....I had Anti running a 6k race     edited 

Orange Dr   =  sqrt  (85^2  - 77^2)  = sqrt (1296)  =  36

77  + 36   =  113

113   -  85    =  28 yds  farther

Glad you are with us   !!!!

1.00 /  120  =   x  / 2370          cross-multiply

2370  = 120 x              divide both sides by 120

19.75 = x  =  US dollars  and cents

Yes Mr.CPhill it i correct, i am glad i made a account on web2.0 calc a very wise decision...!!!!

Yeah....I see I can get something larger

9.7  + 8.6    =  18.3   maybe  ???

Hi! I'm new too! Sophmore here ^^

#2 and 3 are correct but #1 isnt??

3. If a,b ,c ,d and  are four different digits from 1 to 9 , inclusive, then what's the largest possible value for the decimal a.bc + 0.d?

Less sure about this one...I get

    9.86

 + 0.7

_______

  10.56

1. If a,b ,c ,d and  are four different digits from 1 to 9 , inclusive, then what's the largest possible value for the decimal a.b + c.d?

9.8   +  7.6    =  17.4

2. If a,b ,c ,d and  are four different digits from 1 to 9 , inclusive, then what's the largest possible value for the decimal a.b - c.d?

9.8  - 1.2  =  8.6

tysm

-0.123      -0.0123      0.112233       0.1223     0.123     0.125      0.13

   0.125

-  0.0123

________

   0.1127

a. 1 because the number could be any prime^19, which has 19+1=20 positive divisors.

b. 3. We can start by finding the prime factorization of 20, which is 2^2x5 so there must be 3 primes.

W(–1, 4), X(4, 0), Y(–5, 1), and Z(0, –3) are vertices of quadrilateral WXZY. What is true of  wx and yz ?

Thank you very much ElectricPavlolv, appreciate it!!!

The   amplitude  = 8

Here is a possible function :   https://www.desmos.com/calculator/2cbend58si