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would'nt that just be 100?

A difference of x and y squares makes for a hyperbola.

Sorry I'm a bit late, I was sleeping. :))

-cos(x)/(tan(x)-1) = cos(x)/(1-tan(x))  I simply multiplied both sides by -1, and since we now have the same denominator, as sine(x)*tan(x)/(tan(x)-1), we can just add the numerators together. 

As for your method, I think you messed up on the second to third line, you included the -1 outside of the denominator of the fraction. 

=^._.^=

Average (mean) = 19.7  cm    ONE standad deviation (0.4) below the mean is 19.3 cm

   How many wands are below one standard deviation?

    from z-score table   z = -1    equates to   .1587     or 15.87%

(x/2 - 3)^2 + (y/2 + 5)^2 = 10^2       Multiply both sides by 4 to get rid of the fractions

(x-6)²  + ( y+ 10)²  = 4 x 10²

Circle with  center   6, -10     radius   20

1     Sin = opp / hyp  = depth/distance

        sin 28 = depth / 791        take it from here !

2     Pythagorean theorem     4^2 + 4^2 = diag²

                       diag = sqrt ( 32)       take it frome here !

Not to be rude but those two sides of the equation aren't equal. The first one is equal to around 31 and the second is equal to around 35.

this would be a circle because when both the x and the y are squared that makes it a circle.

this is how I do it..but get stuck..

First I swopped the two terms around

\({SinxTanx \over{Tanx-1}}+{Cosx \over{1-Tanx}}\)

\({SinxTanx \over{Tanx-1}}-{Cosx \over{Tanx-1}}\)

\({{(Sinx){Sinx \over{Cosx}}} \over{sinx \over{Cosx}}-1}-{Cosx \over{Sinx \over{Cosx}}}-1\)

\({{Sin^2x \over{cosx}} \over{Sinx \over{Cosx}}-1}-{Cosx \over{Sinx \over{Cosx}}}-1\)

\({{Sin^2x \over{Cosx}}*{Cosx \over{Sinx}}-1}-({{Cosx}*{Cosx \over{Sinx}}})-1\)

\((Sinx-1)-({Cos^2x \over{Sinx}})+1\)

\((Sinx)-({Cos^2x \over{Sinx}})\)

And I'm stuck...

Hi catmg

Actually, I'm a bit lost..I do not understand where you get the first line...

sine(x)*tan(x)-cos(x)

_______________  = sine(x) + cos (x)      

tan(x) - 1

The range is [-10,2].

There are 32,520 ways.

The area of the shaded region is 4*pi.

1. m + b = 3.

2. B - A = 6

Thank you catmg,

very helpfull, I do appreciate..

(2x^2+9)(4x^2−18x^2+81)

I think...

You can just use a calculator...

Answer: 9810131

Find the exact value of 2012-2002+1992-1982 +...+ 32 - 22 + 12 - 2

\(\begin{array}{|l|rcl|} \hline 1.& -2+12 &=& 10 \\ 2.& -22+32 &=& 10 \\ 3.& -42+52 &=& 10 \\ \ldots & \ldots &\ldots & \ldots \\ n-1 & -1982+1992 &=& 10 \\ n & -2002+2012 &=& 10 \\ \hline & sum &=& 10*n \\ & sum &=& 10*101 \\ & \mathbf{sum} &=& \mathbf{1010} \\ \hline \end{array} \begin{array}{|rcll|} \hline &&\text{ finite arithmetic progression} \\ \hline a_n &=& a_1+(n-1)d \quad | \quad a_n = 2012,~a_1 = 12,~ d = 20 \\ 2012 &=& 12+(n-1)*20 \\ 2000 &=& (n-1)*20 \\ 100 &=& n-1 \\ \mathbf{n} &=& \mathbf{101} \\ \hline \end{array}\)

From 1970 to 1992 = 22 years

population grew   161000 - 94000 = 67000

    this is   67000/22 = 3045.45 per year

From 1970 to 2035   is   65 years

65 years * 3045.45/yr =  197954.54 ~~197955        add this to the starting population of 94000= 291955   in 2035

a1 * r * r  = a3

15 r^2 = 135

r^2 = 9

r = 3

an = a1 (3^n-1)

an = 15 * 3^n-1

Break it into two right triangles

  one is  1x1    the other   is  3x2      total area = 1/2 + 3 = 3 1/2 units²

Here is a step by step solution:

Hope this helps.