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dylan had 7x

x=4

answer is 12

Cycle re-ask:

Yes, they are very hard questions and I understand that it may be unreasonable for your educator to give them to you.

BUT

They are not meant to be easy.  Have you seriously tried to learn from the answers that you have already been given?

If they are really way too hard for you it is better that you do not answer them. 

Explain to your teacher that they are way too hard and you do not have a clue how to do them.

Your teacher cannot give you appropriate level work if you keep answering (by cheating) and she/he thinks that you can do these ones.

I got 27 degrees. Here is the link to my work since I couldn't upload a picture for some reason:  https://cocreate.csail.mit.edu/r/SaiBuzcuL4GCaSig6 

f(1) = 125.

hint: add the 2 equations up and then divide by 12

But they're so hard! I came to this website to get help, not by getting mean answers. Plus I'm stuck on question like forever. I can't even do a single thing on it. It's so hard.

Have you tried this question for yourself?

There have been a lot of similar questions asked lately and a number of them have answers.

I expect that they were all asked by you or your classmates.

Have you worked through the answers that are given?

Suppose z is a complex number such that z^2 = 24 + 70*i. Find |z|.

Hello Guest!

\({\color{blue} |z|}=|\sqrt{z^2}|=|\sqrt{24+70i}|=|7+5i|=|\sqrt{74}|\color{blue}=8.60232...\)(so at WolframAlpha)

  !

2 b / 12 c  * 200 c = 33.33 b     ~~ 34 sticks of b utter    ( notice how the 'c' cancels out and you are left with b utter)

Depends on the value of n

How many negative integers m satisfy the inequality 3/m <= -7/22?

Hello Guest!

\(\dfrac{3}{m}\leq -\frac{7}{22}\\ \color{blue}m\geq-\frac{66}{7}\\ \color{blue}m\geq -9.\overline{428571}\)

\(m_{\mathbb Z}\in -\mathbb Z\ |\ -9\leq m\leq -1\)

\(m_{\mathbb Z}\in \{-9,-8,-7,-6,-5,-4,-3,-2,-1\}\)

9 negative integers m satisfy the inequality 3/m <= -7/22.

  !
 

y coordinate is   - 1/2

Find the distances between the x's and y's, then divide by two to find the midpoint.

(-2-8)/2=-5

(-2-1)/2=-3/2

(-5, -3/2)

sorry i don't know how to do LaTeX

First, I will multiply the top and bottom of the fraction 8/9 so the bottom is even.

If Tom originally had 8/9 of the sweets and gave away 42 to make it equal, that shows that 42 sweets is exactly 7/18 of the total. We can then create the equation with x being the total sweets they were given:

x * 7/18 = 42

dividing each side by 7, we get

x/18 = 6

so we can multiply each side by 18 to get

x = 108

:)

So if 2 sticks of butter make 12 cupcakes... and we set the number of cupcakes as c and the number of sticks of butter as b, we get

12c = 2b

dividing each side by 2 we get

6c = 1b

Since we need 200 cupcakes, we divide 200 by 6 and get 33.3, which we round up because we need 200 cupcakes or more

so we multiply the equation 6c = 1b by 34, and get 34 sticks of butter

:)

Let the number of Liters of 3% solution==T

Then the number of Liters of 18% solution ==15 - T

0.03T +  0.18[15 -  T]==0.08 * 15

0.03T +  2.7  -  0.18T ==1.2

0.18T  -  0.03T ==2.7 - 1.2

0.15T ==1.5

T ==1.5 /0.15 ==10 Liters of 3% solution.

15  -  10  ==5 Liters of 18% solution.

a hamster eats 11 g of food a day how much food does it eat in the month of april

what is the answe to this question  

30 days hath September, April, June, and November  

(11 gm/day) • (30 days) = 330 grams  

_.

In a set of five consecutive integers, the smallest integer is more than 4/5 the largest. What is the smallest possible value of the sum of the five integers?     

If the set were 16 thru 20 the ratio of the smallest to the largest is 16/20 = exactly 4/5.  

Since the problem specifies more than 4/5, then the set of integers is 17 thru 21.  

17 + 18 + 19 + 20 + 21 =  95  

_.

yes i figured after i posted the question.. thanks 

The number is 110, which has factors  1, 2, 5, 10, 11, 22, 55, 110

EP's result is 720 lights.

1/3 of 720 is 240 so each small tree has 240/12 = 20 lights.

The remainder is 720 - 240 = 480 lights.  3/4 of 480 = 360 lights, so each big tree has 360/10 = 36 lights.

Therefore each big tree has 36 - 20 = 16 more lights than each small tree.