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plug -3 into the first equation, 0 into the first one as well, and 3 into the second one in order to meet all the conditions of the two functions.

This is a general thing about piecewise functions-- in this particular case, if x is any value less than or equals 1, you would plug x into the first equation.

f(-3)=5, f(0)=2, and f(3)=6-3^2=-3.

Adding them all up together we get the answer 4.

Hope this helps

Using negative exponent and reciprocal rules, we have:

27-(-27)

The second 27 is negative since if we have an odd exponent and a negative base the result is negative.

So the answer is 54

Hope this helps

0, 1, 2, 4, 5, and 7.

So that would be 6 digits. 

Sorry, my internet lagged out when I was posting this and it didn't save. Here's the right answer: -1 < x < 1

Four questions are guessed randomly. Each question has 5 choices, one of which is correct.

So there are 625 permutations of answers and a 1/625 chance of getting every question right.

The easiest way to solve this is to use complementary counting. Find the number of cases where he gets 1 correct or none correct.

There is a 4/5 chance of getting each question WRONG. So the probability of getting them all wrong is 256/625.

The probability of getting ONE AND ONLY ONE correct is 1/5*4/5*4/5*4/5(the order doesn't matter here)=64/625.

Adding them up together, we get 320/625. But these are only the cases that we don't want, so we have to subtract from the total.

625-320=305. So the answer is 305/625=61/125.

I will leave you to check any possible errors. But you get the idea 

Total 12 marbles    5 are red       5/12   chance red on first draw

    now there are 11 marbles left   4 are blue    4/11 chance blue on second draw

5/12 * 4/11 = .........

Since BC and DE are parallel, triangles BCF and DEF are similar. So the ratio of corresponding sides between those two triangles are the same.

20/10 = y/9 = BC/DE. y=18.

Hope this helps

Literally just use basic 1st-2nd grade additive computation(depending on where you live) to find the answer by lining up the first number with the second and carrying numbers using our wonderful base 10 system.

3758699452+95735546836524768 = 95735550595224220

We can eliminate y by subtracting the first and second equations and add the second and third equations.

So we have two equations and two variables now:

4x+2z=-12

-3x-z=9

Now we can use the elimination method to eliminate z by multiplying the bottom equation by 2 and adding it with the bottom.

-2x=6 x=-3

so now we know z=0 by substituting x into the previous equation.

similarly, we can find that y=1 by substituting x and z into any of the orig equations

Hope this helps

rectangle    5 x 3   cm²

              +

Trapez      4 x (10+5)/2  cm²    

twenty three   (prime number between 20 and 28)

https://web2.0calc.com/questions/help-is-appreciated_15

Calculate 5! + 6! + 7! + 8! + 9! + 10! + 11! + 12!

What do you notice about 10!, 11!, and 12!?

=^._.^=

Law of cosines

7^2 + 6^2 - 2(7)(6)cos a  = 12^2      solve for cos a

Pick an amount to finish with...say 100cc

x = x amount      100-x = y amount

.1x   +   .2(100-x) = .16 (100)

.1x + 20 - .2x  = 16

.1x  = -4

x = 40      then   y = 60        x:y is then  40:60  =  2:3

420.89 ft²

37.5%   ( or 3/8 ths)

Point - slope form of the line

(y- -3) = 2 (x-2)        y intercept ocurs when x = 2      sub that in to find y value

Initially

1/5 h = 3/7 j     re-arrange

h = 15/7 j

then

h -356 = j+428      sub in the red equation for h

15/7 j -356 = j+428        then you can solve for j      use this value to solve for h  

                                           then  subtract 356 from h  and add 428 to j ( the results should be the same)     and add them together..... 

When the ball hits the ground h = 0

0 = -16t^2+32t+128     Use quadratic formula to find t values....throw out negative value...

x = original salary

1.16 x  = new salary

1.16 x = 58 000

x = 58 000 / 1.16

2 big jars contain 0.3 kg more sugar 

than 3 small jars

     2b = 3s + .3

       re-arrange to   s =   (2b-.3)/3

5b + 2s = 8.35      total    now substitute in the red equation for 's'

5b  + 2(2b-.3)/3  = 8.35

b = 1.35 kg   per jar          now multiply by 5  (since there are 5 big jars).......