g = w
5 (g-60) = ( w-20) sub in g = w
5w - 300 = w - 20
w = 70 and g = 70 they brought 140 dollars (70 dollars each) .....
Let's see who's right: guest 1, or guest 2
7/14 = (14 - YZ) / 7
49 = 196 - 14(YZ)
14(YZ) = 147
YZ = 10.5
Missing diagram.....
210 - 10 C 2 - 10 C 1 - 10 C 0 = 1024 - 45 -10 -1 = 968 possible sequences
(10 C 3) + ∑ (n, 4, 10, (10 C n))==120 + 848 ==968 sequences of tosses.
212 - 53 = 159 weird stickers
x y
216 1 108 2 72 3 54 4 36 6 27 8 24 9 18 12 12 18 9 24 8 27 6 36 4 54 3 72 2 108 1 216
Add up all the "x's"
3x^2 + 14x + 8 = 7x + 14
3x^2 + 7x - 6 = 0 Quadratic Formula shows x = 2/3 and -3
That answer is incorrect .... that would bean that B had 1/4 (375) = 93.75 stickers
see my steps above....
375 is the answer of stickers Alex had first
If a + b = -8 , and b + c = 3, and a + c = 5. Then what is a times b times c ?
c + b = 3
a + b = –8
c – a = 11
c + a = 5
2c = 16 —> c = 8
8 + b = 3 —> b = – 5
a + c = 5
a + 8 = 5 —> a = –3
Check a, b, & c values:
a + b = –8 —> –3 + (–5) = –8
b + c = 3 —> –5 + 8 = 3
a + c = 5 —> –3 + 8 = 5
a • b • c = (–3) • (–5) • (8) = 120
.
Initially:
a = 4b
3(a-203) = (b-26)
3 ( 4b-203) = b - 26
b = 53 then a = 4b = 212 < ====finish from here
Giving away 1/8 leaves 7/8 ths
x = originl amount
7/8 x - 1/8x-16-24 = 56
x = 128 cans
midpoint is (8+6)/2 = 7 = x
from 12 to -14 for y is distance 26 ....1/2 is 13 from 12 = -1 (7-1) <==== finish from here
six 50 20 10 5 2 2
c + m = 400
or
c = 400 - m
selling 1/9 leaves 8/9
8/9 c = 4 ( m-15)
8/9 ( 400-m) = 4m - 60
8/9 (400) - 8/9 m = 4m - 60
m=85 then c = 315 only 8/9 of the 315 is left = 280 chicken sticks
I didn't type that. Probably a guest impersonating me.
Oh i had it in doubt
No.....You got it CORRECT !
310 answer?
From 3 to 1 is a distance of 2 go 2 more to x = -1
from 9 to -2 is a distance of 11 go 11 more to y = -13
Note: there are many different ways to write the result. Are you sure what you did is incorrect, or is it just expressed differently from the answer supplied?
How many 3 digit numbers can be made using the digits in the list (1,2,3,3,3,9)?
333 one number
33(not3) 3*3=9 numbers
one or no threes 4P3 = 24 numbers
so that is 1+9+24 = 34 numbers
a + b + c = 9 square both sides and simplify to
a^2 + b^2 + c^2 + 2 (ab + bc + ac) = 81
a^2 + b^2 + c^2 + 2 ( 26) = 81
a^2 + b^2 + c^2 = 29
c = 50 + s
then
c - 3/5 c + s - 1/2 s = 137
2/5 c + 1/2 s = 137 Plug in the red equation for c ....then solve for s then solve for c = 50 + s then add together