How many apples does Alvin have initially?
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x apples does Alvin have initially.
\(B= (\frac{1}{3}x+\frac{2}{3})\)
\(C=(\frac{1}{4}(x- (\frac{1}{3}x+\frac{2}{3}))+\frac{1}{2})\\ C= (\frac{1}{4}(x- \frac{1}{3}x-\frac{2}{3})+\frac{1}{2})\\ C=(\frac{1}{4}x- \frac{1}{12}x-\frac{1}{6}+\frac{1}{2})\\ \color{blue}C= (\frac{1}{6}x+\frac{1}{3})\)
\(D=(\frac{1}{2}(x- (\frac{1}{3}x+\frac{2}{3})-(\frac{1}{6}x+\frac{1}{3}))) \\ D=(\frac{1}{2}x- \frac{1}{6}x-\frac{1}{3}-\frac{1}{12}x-\frac{1}{6}) \\ \color{blue}D= (\frac{1}{4}x-\frac{1}{2})\)
\(E= (\frac{1}{2}(x-(\frac{1}{3}x+\frac{2}{3}) -(\frac{1}{6}x+\frac{1}{3})-(\frac{1}{4}x-\frac{1}{2}))+\frac{1}{2}) \\ E= (\frac{1}{2}x-\frac{1}{6}x-\frac{1}{3} -\frac{1}{12}x-\frac{1}{6}-\frac{1}{8}x+\frac{1}{4}+\frac{1}{2}) \\ \color{blue}E= (\frac{1}{8x}+\frac{1}{4})\)
\(x=(B)+(C)+(D)+(E)+5\)
\(x=((\frac{1}{3}x+\frac{2}{3})+(\frac{1}{6}x+\frac{1}{3}) + (\frac{1}{4}x-\frac{1}{2})+(\frac{1}{8}x+\frac{1}{4})+5)\\ x=0.875x+5.75\\ \frac{1}{8}x=5.75\)
\(x=46\)
46 apples does Alvin have initially.
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