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floor[1234 / 7^1]  +  floor[1234 / 7^2]  +  floor[1234 / 7^3] ==204

1234!== 2^1229 * 3^614 * 5^305 * 7^204 * 11^122.......and so on. 

x / 13 = (9 + x) / 26

26x = 13(9 + x)

13x = 117

x = 9

3/10X + 17 + 7/10X - 7/20X = 121

X = 160

160 (3/7) = 48 red

160 (7/10) = 112 white

160.

final total is 121 after adding 17 roses so after giving away half white total is 104

initial mix is 3/10 red and 7/10 white after giving away half white total us 6.5/10 or 13/20

Divide 104 by 13/20 104/13*20=8*20=160

mm

experiment

1) How many times does 3 go into 10!

3*6*9      3 3 3 3  four times

10/3 = 3 and a bit

3 and a bit/3 = 1 and a bit

3+1=4

-------------------------------------------------

1234/7 = 176.2857142857142857

176.2/7 = 25.1

25.1/7 = 3 and a bit

3+25+176 = 204

So I think    204

1/3    +    3^-1    + 3^-1     + 3^-1 ..........+ 3^-1

^{=   1/3  *  3000 = 1000}

Let the cost of each pendant is x then the cost of

6 pendant is 6x.

Given each necklaces has a pendant

Hence, the cost of pendant for all 6 necklaces is 6x

Given, the cost of total beads is $14.40

Hence, the total cost of the beads and pendants of

all 6 necklaces is 6x + $14.40.

Given, the total cost of the beads and pendants of all

6 necklaces is $31.80

Hence 6x + $14.40 = $31.80

           => 6x = $17.40

           =>   x = $2.90

Hence, the cost of each pendant is $2.90

wouldnt k=1 work?

Thank you!!!! 

1,849    rounded to nearest tenth is 1849

1.849 rounded is  1.8

y = b    ??

  Too late to edit.  Disregard reasoning. 

  The question says 1^2009 + 2^2009 + 3^2009 etc., but 

  my feeble mind saw 1^2009 x 2^2009 x 3^2009 

_.

What is the ones digit of 1^2009 + 2^2009 + 3^2009 + ... + 100^2009?  

0 (zero) ... Once you get a zero into the units position – and 10²⁰⁰⁹ is the first place it will be introduced – that zero stays there no matter how many times, or by what, you multiply it.  

_.

 2013^(2013^2) mod 13==8 - the remainder

There are NO such 5-digit numbers! Did you make it up?

There are 2 such 4-digit numbers as follows:

3990 , 7980  Total =  2

The following should help you answer that:

This can be written as \(\frac{x^2}{13^2}+\frac{y^2}{5^2}=1\), so the semi-major axis is 13, the semi-minor axis is 5, and its centred on (0, 0).

Can you take it from here?

As follows:

sin A = 2 cos A

sin/cos = 2

tan = 2

arctan =  63.4349

  sin  63.4349 =  .894427

4/52    *     3/51    *     2/50    *     1/49   =

You can do some of this GM

Factorize each of the 4 bits separately.

and

To divide by a fraction you invert and multiple (the second one)

Your turn now  

Where is your pic?

HoldMyBeer's answers are correct:

BE = 2.5 units