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The probability is 67/144.

$f(x) = \frac{x}{(x + 1)^2}$.

A = 2B + 7.

The probability is 2813/7776.

The largest possible number is 8/45.

Wherever the DENOMINATOR = 0 , this expression is not defined

(x^2 -24x+100) = 0

    Use quadratic formula to calculate the values of 'x' that result in this = 0        a = 1      b = -24      c = 100

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

There are 2 angles that are equal in an isosceles triangle

maybe it is   2d - 40

   then  2 ( 2d-40) + (d+10) = 180           solve for this value of  d

maybe it is   d+10

   then  2 ( d+10 ) + (2d-40)   = 180        solve for this value of  d

Complete the square for x and y

x^2 -18x      + y^2 - 24 y =     -124

(x-9)^2        + ( y -12)^2  =  - 124 +81 + 144     <===== the red part = r^2

                                       =  101                                r = sqrt (101)

9 + 5 = 14     would be 2   (0'clock)

n

1 GCD== 1
2 GCD== 2
3 GCD== 1
4 GCD== 4
5 GCD== 1
6 GCD== 22
7 GCD== 1
8 GCD== 4
9 GCD== 1
10 GCD== 2
11 GCD== 1
12 GCD== 4
13 GCD== 1
14 GCD== 2
15 GCD== 1
16 GCD== 4
17 GCD== 11
18 GCD== 2
19 GCD== 1
20 GCD== 4
21 GCD== 1
22 GCD== 2
23 GCD== 1
24 GCD== 4
25 GCD== 1
26 GCD== 2
27 GCD== 1
28 GCD== 44
SUM of all GCDs ==126

Note: if you wish to count only UNIQUE GCDs, then you have: 1, 2, 4, 11, 22, 44==84

Merry Christmas to everyone. :DDD

=^._.^=

The form of the answer is correct but it seems like the constant k is a bit off.

Thanks

Thanks Straight,

A very merry Christmas to you too.

Merry Christmas to everyone!

This question doesn't quite make sense to me.

if v is a set constant but theta is variable (which is not stated)

then I got the max area when theta = pi/6

The max area would be   \(\frac{\sqrt3}{24}*\frac{v^4}{g^2}\)

I have not checked my working and it could easily be wrong but it is at least in the form that is asked for.

If you want to ask questions feel free to do so.

the minimum positive value of p is 4.

When y = 3, x = 5/3.

The sum of all y is 6.

The sum is 84.

Yea it is ya dun dum, but thia answer is this

q93269184098162394816239408163204896123984612398461982364123984610923846918236429384691028364192111111111111111111111111111111111111111111111111111111111dhfdfasdfasdfasdfajsdlfjhaodsihfo;aisdhfoiasdhfoiahsd;ofihas;doifh;osdigheihtgowirdhtg;oiawhei;owsgiouwsiodgh;asodiufhpsodhf

It's 82394y198498132 u dun dum

There seems to be missing text, can you fix this please?

Ever 5th Fibonacci number is divisible by 5. Since you have 1,000 terms, then that means:

1,000 / 5 ==200 terms that are divisible by 5.

4 < sqrt(n) < 100, solve for n

16 < n < 10000

{1, 2, 3, ........50} mod 8 ==2

You have the following numbers: 2,  10,  18,  26,  34,  42, 50 ==7 integers congruent to 2 mod 8

Therefore, the probability is: 7 / 50