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x= 2y+4

 use this 

See https://web2.0calc.com/questions/counting-problem_42434

See https://web2.0calc.com/questions/counting-problem_42434

See https://web2.0calc.com/questions/counting-problem_42434

If you graph it, the maximum value is 361 when x=2.5

Combining like terms and rearranging the equation: x²+8x+y²-8y=88

Then you would complete the square for the x and y: (x+4)²-16+(y-4)²-16=88. You subtract 16 for both to keep the equation the same. Moving then to the left side gives (x+4)²+(y-4)²=120. This is the equation of a circle with a radius of \(\sqrt{120} \).

Then you just find the area using the radius.

Hope this helps!

13 is prime, so we know we can write it as (13x _ _)(x _ _)

17 is also prime so we can guess put it into either one as (13x - 17)(x + 1) or (13x + 1)(x - 17) or (13x - 1)(x + 17) or (13x + 17)(x - 1).

FOILing it out:

(13x - 17)(x + 1) = 13x^2 - 4x - 17

(13x + 1)(x - 17) = 13x^2 - 220x - 17

(13x - 1)(x + 17) = 13x^2 + 220x - 17

(13x + 17)(x - 1) = 13x^2 + 4x - 17

Values of n: -220, -4, 4, 220

1/(a^3 + 7) = -a^3/(a^3 + 7), solve for a

The denominators cancel out and you are left with:

a^3 = - 1

a = -1
a = (-1)^(1/3)
a = -(-1)^(2/3)

Ok first off, there is a difference between solutions and answers. You should know as you are on this site.

2. Can you show your work? I literally plugged those in and they do not seem to satisfy the equation?

3. If this is done intentionally, please stop. You are just literally wasting your time going on random questoins and "answering" them. 

Please be aware that the Guest who 'answered' your question did miss a lot of steps. And there is no such thing as "theory of continued fractions"???

I would recommend you checking this out. https://web2.0calc.com/questions/deliberately-misguiding-answers#r2

Denote y = x-1

y = 1/(2 + 1/....

1/y = 2 + 1(2 + 1/(2..

1/y - 2 = y 

y^2 = -2y + 1

y^2 + 2y - 1 = 0

By Quadratic Formula,

y = -1 +- sqrt(2)

Because y has to be nonnegative, y = -1 + sqrt(2)

y = x - 1

-1 + sqrt(2) = x -1

x = sqrt(2) 

A=2(wl+hl+hw)

This is the surface area formula of a rectangular box, which is what you have !

w =width,  h=height,  l=length

A=6 a^2? Why does it matter

Let me just make sure you know the surface area formula. Post it down below

Did you look under your last posting of the same question here: https://web2.0calc.com/questions/help-plz_89821

Sorry, it  wasn't right