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The probability of winning a super prize is the sum of the probability of matching at least two white balls and the probability of matching the red SuperBall.

The probability of matching the red SuperBall is 1/8, as there are 8 red balls and only 1 is drawn.

The probability of matching at least two white balls is a bit more complex to calculate. To match at least two white balls, we can either match exactly two or exactly three.

The probability of matching exactly two white balls is: (3 choose 2) * (12-3)/(12-3) * (12-2)/(12-2) = 3 * 11/12 * 10/11 = 30/44

The probability of matching exactly three white balls is: (3 choose 3) * (12-3)/(12-3) * (12-2)/(12-2) * (12-1)/(12-1) = 1 * 11/12 * 10/11 * 9/10 = 9/22

So, the probability of matching at least two white balls is: P(matching at least 2 white balls) = P(matching exactly 2 white balls) + P(matching exactly 3 white balls) = 30/44 + 9/22 = 39/44

Therefore, the probability of winning a super prize is: P(winning a super prize) = P(matching at least 2 white balls) + P(matching the red SuperBall) = 39/44 + 1/8 = 39/44 + 2/44 = 41/44

b)

give them one each to start with then there are 15 stickets left

lie up the stickers  divide them into  5 bundles (some bundeles can be empty) the order of the bundles count becasue they are to be given to the five friends who are standing in a row.

 You need 4 dividers to do this

so you have 15+4 items = 19

19C4 = 3876 ways.

Use the same logic to get a)

This technique is called stars and bars method if you want to look that up.

No one can help you if you do not proofread your questions

Presenting nonsense helps no one.

12C3 = 220

This should work I think

the side length of the dark little triangle is half that of the large triange.

All the points inside the little triangle will be closer to the centre (which in my pic is J) than they will to any side ot the big triangle.

The sides of the little to big are in the ratio 1:2

So the are of the little to big will be 1:4

The area of the little to the area in the big, not including the little wil be  1:4-1   =    1:3

So probability that the distance to the centre is less than the distance to the edge is 1:3   i.e.    \(33.\dot3\;\%\)

Your answer is wrong, however, I am not sure why. Please show how you got to your answer

a = 1/2, b = sqrt(3)/2

cos(arccos(3/5)+arcsin(-4/5)) = 24/25

10c = 2*sqrt(2) + 3

10d = 8*sqrt(2) - 3

on the 2d graph there are 4 directions up down left and right

up = +y

down = -y

left = -x

right = +x

since you want to move 8 units left and 6 units down we can subtract 8 from the first coordinate and 5 from the second coordinate

8-8 = 0 and 13-6 = 7

the desired point is (0,7)

Sorry Guest the correct answer is C x > 1

Why is this true?

we can start by subtracting 2 from both sides

-26+13x+2>2-13x

-26+13x>-13x

again simplifying by adding 26 and 13x to both sides

26x>26

dividing both sides by 26

x>1

Since you are looking for an x intercept you can set y = 0

this looks like trig identities

https://www2.clarku.edu/faculty/djoyce/trig/identities.html should help

please include the diagram

I can't see the rectangle

I answered this question from your account here

https://web2.0calc.com/questions/asap_42

please avoid posting the same question multiple times on the same day

Hey THEORANGECATISHERE

61.54 + 13.43 = 74.97

hope that helped

I believe this is the proper notation:

Five Hundred Twenty Five Thousand One Hundred Seventy Four

no, that is incorrect, but why would R and T be equal to \(\theta\)/2

we start with 3(2c+1) = 28(3*c) - 9

(just to note 3*c = 3c)

we expand the equation by multiplying the numbers left unmultiplied

3(2c+1) = 6c+3

28(3c) - 9 = 84c-9

we move the 6c+3 to the other side of the equation by subtracting 6c+3 from both sides

84c-9 - 6c - 3 = 0

78c - 12 = 0

isolate the variable by adding 12 to both sides

78c = 12

then divide both sides by 78

c = 12/78

simplify 

c = 12/78 = 2/13

c = 2/13

I hope this explanation helped you :)

We start with 2 types of numbers:

one with variable X

one with no variable or a constant
We start by adding the numbers with variables
(1/7x + 3/8) + (2/7x -1/8)

1/7x+2/7x = 3/7x

you can repeat the same process with the constants

3/8-1/8 = 2/8 = 1/4

so the simplified version = 3/7x+1/4

Let the time taken to get to the beach==T

Then, time taken to get to the park ==2T

8T  +  7(2T) ==20, solve for T

T ==10 / 11 ==54.545454......minutes - time taken to get to the beach

54.545454......  x   2 ==109.090909.......minutes - time it took him to get to the park.

The number of possible planes is 12/3 = 4.

A=2/3, or 0.66 repeating

B=1536

C=8/25, or 0.32

D=-16

E=3sqrt(2), or 4.24

D, C, A, E, B