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In the two factored term, does the last number of the first factor when multiplied by the last number of the second factor have an answer of -22? If so, it is a possible answer; if not, it isn't.

Now, does the last number of the first factor when added to the last number of the second factor have an answer of +9? If so, it is a possible answer; if not, it isn't.

There is only one possible answer that answers both of the above questions "Yes!"

Since the last term is positive, either both signs are positive or both signs are negative.

Sine the middle term is negative, both signs are negative. This eliminates two of the possible answers.

Now, you will need to multiply the two numbers of the last term to get 36 and (ignoring the sign) add the two numbers of the last term to get the middle term; this will give you the right answer.

6 x 6 = 36  Does 6 + 6 = 12?

9 X 4 = 36  Does 9 + 4 = 12?

(1 googol)²  =  (10^10^100)²

(k + h)³  =  (k + h)[(k + h)²]  = (k + h)[k² + 2kh + h²]

                = k³  + 2k²h + kh² + hk² + 2kh² + h³ 

                = k³  + 3k²h + 3kh² + h³ 

You may want to check out Pascal's Triangle on the net, or ask your teacher for a quicker way.

9+10=19 i have a great brain

4+4=8

i know that 4+4  8

a woodchuck would chuck as much wood as a woodchuck could chuck if a woodchuck could chuck  wood

Four + Four = eight 

4 + 4=8

In the second problem, since you know SSS, use the Law of Cosines.

m² = l² + n² - 2·l·n·cos(M)

14² = 17² + 11² - 2·17·11·cos(M)

196  =  289 + 121 - 374·cos(M)

196  =  410 -374·cos(M)

-214  =  -374·cos(M)

0.57219  =  cos(M)

M  =  55.1°

9 x 2e  =  18e

a +4 ≥ 8                                              (Subtract 4 from both sides.)

a + 4 - 4 ≥ 8 - 4

a ≥ 4

2a(2a² +2ab + 1)                          Using an extended distributive property:

2a·2a² + 2a·2ab + 2a·1

4a³ + 4a²b + 2a

Thanks CPhill, that means alot to me.

9.8596 thats the full awnser unless your rounding the number

3x+7+=-8=13 x=13

also if u can pls post photos of the steps of the cross method IF U CAN thx

7  >  x/4 + 2                       First subtract 2 from both sides:

5  >  x/4                             Now multiply both sides by 4:

20  >  x

This doesn't seem to be fully explained.

If all of them weigh 50 pounds, they weigh 50 pounds.

Turn each of the fractions into common fractions and multiply by the reciprocal.

For example:  2 3/4  ÷  5 1/3

  2 3/4  =  (2 x 4 + 3) / 4  =  11/4

  5 1/3  =  (5 x 3 + 1) / 3  =  16/3

11/4  ÷  16/3     =     11/4 x  3/16      =  33/64       (Multiply 11 x 3  and  4 x 16.)

This is an AAS (or SAA) triangle, so use the Law of Sines.  Since you want to find a side, use this form:

c/sinC  =  a/sinA

c/sin(67) = 12/sin(34)

c = 19.8

I have a really good calculator, and it tells me that 9 + 10  =  19.

When you say "3x to the 5th power" do you mean (3x)^5 or do you mean 3(x^5)?

If it is the first case, you would get 8·(3x)^5  =  8(3x)(3X)(3X)(3X)(3X)  =  1944X^5.

If it is the second case, you would get 8·3(x^5)  =  24x^5.

For my first answer, I didn't see the word "times"; I just added the two parts ...

Did you mean that -5a² was to be multiplied to -11a²?

-- If so, multiply -5 times -11 to get 55     and multiply a² times a² to get a^4, 

    for the answer  55a^4