All Answers 358460 Answers

993 is divisable by 3    

i sorta chose 993.

inverse trig is the same as arc trig

Therfore use atan, asin and acos     

You have to hit [2nd] first.

or

if you just hit sine and linger there for a bit longert than usual, it will turn into asin   

Sorry naynay but this doesn't make sense

If you mean

c+d=56 then there is an infinite number of paired answers.

eg.

c=3 and d=53

or

c=12 and d=44

Thanks!

the region is a circle, diameter is BC. the area is pi*BC*BC/4 = pi*200/4 < 157.

157 is the answer.

Use a calculator?

well yeah you have to do that just anser the question

6889-678+432=.....

It is pi

zzzzzzzzzzzzzzzzzzzzzzzz... what?

no, 8.637.

$${\frac{{\mathtt{125}}}{{\mathtt{1\,000}}}}$$

It has to be in factions

measure the sides first then times it by 2. e.g.$${\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{48}}$$. then, like my formula, the ansewer is $${\mathtt{48}}$$.

I think no, possibly.

you are missing a "n"

3-1 is 2. (and by the way, LOL!)

Dont lisren to the other ansewer, the real ansewer is 19.

the ansewer is 0.125.

or... $${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{2}}$$ and 2+2.

Easy.$${{\mathtt{2}}}^{{\mathtt{2}}}$$ is 4.

(z^5)^3   =   z^15

If you have an exponent to an exponent, mutiply the exponents together.

You can think of it this way, you have 3 groups and there are 5 in each group, so you have 3 x 5  =  15.

Since  z^5  =  z·z·z·z·z,

     (z^5)^3  =  (z·z·z·z·z)^3  =  (z·z·z·z·z)·(z·z·z·z·z)·(z·z·z·z·z)  =  z·z·z·z·z·z·z·z·z·z·z·z·z·z·z  =  z^15

I don't understand  -3\le x < 7

Should the  "\" be "/"?

Should  "le"  be  "ln"; if not, what is "le"?