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No OAK grove middle school

The formula for continuous compounding:  A  =  P·e^(r·t)

For this problem, let's assume that you start with $1.00 and you end with 20% more, that is, $1.20.

A  =  final amount = 1.20                 P  =  beginning amount = 1.00

r  =  rate (as a decimal) = 0.035        t  =  number of years

--->     1.20  =  1.00·e^(0.035·t)

Divide both sides by 1.00:

--->     1.20  =  e^(0.035·t)

Take the  ln  of both sides:           ln(e^x)  =  x     --->     ln( e^(0.035·t) )  =  0.035t

--->     ln(1.20)  =  0.035·t

Divide both sides by 0.035:

--->  t  =  ln(1.20) / 0.035  =  5.21 years

You don't have to start with $1.00; you can start with any amount, just so you end with a number that is 20% larger.

(This formula is also known as the 'shampoo formula'.)

do you mean elk??

1-+19 = 1-19 = -18

$$8^{1/2}=\sqrt8 = \sqrt4 * \sqrt2 = 2\sqrt2$$

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}} = {\mathtt{0}}$$

What do you need help with?

[ 1/x² + 1/y² ] / [ 1/x + 1/y ]

Look at all the denominators; their common denominator is x²y².

Multiply both the numerator and the denominator of the fraction by x²y²:

Numerator:  [ 1/x² + 1/y² ] · x²y²  =  y² + x²  =  x² + y²

Denominator:  [ 1/x + 1/y ] · x²y²  =  xy² + x²y  =  xy(x + y)

Answer:  [  x² + y² ] / [ xy(x + y) ]

(You can't simplify any farther.)

This problem is so much easier on a digital clock ... but ...

There are 360° in a circle.

Between any two numbers on the clock, there will be 360° ÷ 12  =  30°.  (This means that the hour hand moves 30° when going from 4:00 to 5:00.)

I'm going to measure all the degree from 12:00 going in a clockwise direction.

First, let's just consider the hour hand.

At exactly 4:00, the hour hand will be 4 x 30° = 120° from 12:00.

At 4:09, the hour hand will go another 9/60th of the distance from 4:00 to 5:00.  (9/60) x 30° = 4.5°.

So the hour hard will be 120° + 4.5° = 124.5° from 12:00.

Now, let's consider the minute hand. After 9 minutes, it will be 9/60th of the way around the dial, so it will be (9/60) x 360° = 54° from 12:00.

The distance between the two hands is:  124.5° - 54°  =  70.5°.

Did you mean 2/5 or 2.5?

a - 3.5 < 2.5                                     a - 3.5 < 2/5           

Add 3.5 to both sides:

a < 6.0                                                a   < 3.9

First draw the picture on a graph.

Then, there's a couple of things that you can do:

   Since it says add 5 to each x-value and subtract 2 from each y-value;

    ---   For each corner point, find a new corner point 5 spaces to the right and 2 spaces down, then                                    connect these points to get the new picture.

    or you can:

    ---   For each corner point, take the x-value and add 5, take the y-value and subtract 2, then graph these                         points and draw the new picture.

Either way, you should get the same new picture (this new picture is the image).

(x - 3)²  =  64

Find the square root of both sides:          (don't forget to use the ± sign)

x - 3  =  ± 8

So, either  x - 3  =  8          or          x - 3  =  -8              (now add 3 to both sides)

                    x  =  11         or               x  =  -5

i hate alegbra i have a high D

oh yeah we're doing sqaure root methods... lol!

oh... okay sorry! i guess my class isnt there yet (im in algebra 1 too)

no its a power?!

You can look under "Sticky Topics" if you want to know how to type fractions.

is ^ multiplying? if so...

use distributive property even though the 2 is behind the parentheses

2x - 6 = 64

now add 6 to both sides

2x = 70

now divide by 2 on both sides

x = 35

and there's your answer!

well in my book its says "first draw ABCD. find the translation of each vertex by adding 5 to its x coordinates and subtracting 2 from its y coordinates then draw ABCD and its image"