All Answers 358110 Answers

Not to be mean but yours is not a possiblity because you used subtraction and you can only use addition and multiplication.

You doubt they could beat ANYONE?????  Then why have they won 5 games this year,  and 2 in a row????

You doubt they could beat SMU Mustangs....who are 0-9?  (They aren't playing them,  just saying)

AAAAARRRGGHH!!!!

Brittany,  when you get on and answer this, tell CPhill he is WRONG about Michigan and Notre Dame.

I didn't want to post the one with Ohio State....I was a afraid to admit they'll probably win.....because Ohio State is my least favorite, but they play Indiana for crying out loud.

Florida better lose.......they better lose.......

And what is about the Cardinals that are playing the Irish??  Same record as Dame....and they've got more skill in my opinion

Huh?                

I don't like ND......I'm just picking them...

I don't trust the Wolverines to beat ANYONE......!!!

Hee's another possibility......

[(1 + 9) + (7 + 8) ] * [(6-5)+(4-3)]*2 =

[10 + 15] * [ (1) + (1)]*2 =

[25] * [2]*2 =

[25] * [4) =

100

P.S. - I still like yours better......

Oh....me totally.....but she is a girl

NOTRE DAME!!!!!  OF ALL THE TEAMS,  NOTRE DAME??????!!!!!!!!

You do know the lost in Northwestern last week.....and Northwestern isn't that good.  Dame could beat Michigan,  Michigan could beat Northwestern,  and Dame can't.  Seriously?

I love Michigan.....GO BLUE!   I predict it will be close.

I was stunned for Wisconsin and Iowa.  Iowa is pretty good,  and Wisconsin is.  I just thought Iowa would barely win

Intersection is what they both share the same of.

So yours would be 4 and 7 because it is in both groups.

I only differ on 3......

I like Mayland....Notre Dame....and Wisconsin

A ratio is showing the relation between two amounts. Showing the number of times one value contains or is contained within the other.

-Google

$${{\mathtt{7}}}^{-{\mathtt{2}}} = {\frac{{\mathtt{1}}}{{\mathtt{49}}}} = {\mathtt{0.020\: \!408\: \!163\: \!265\: \!306\: \!1}}$$

I'll give this one a shot

The probabilty that 2 planes use runway 1 is (1/2)^2

The probability that 1 plane uses runway 2 is (1/8)^1

The probability of three planes u8se runway 3 is (3/8)^3

And we have 6! arrangements of these probabilities....but some are indistinguishable from others. So, the number of distinguishable arrangements is 6! / [ 2! * 3!] = 60

So the probability is .... 60*(1/2)^2*(1/8)^1*(3/8)*3 = 0.098876953125 = about 9.8%

In who can answer questions first.

625% for 46/7.36=6.25  Take away the decimal point and a percentage sign

Since 1 is the square of 1  and 10000 is the square of 100....there must be 100 perfect squares in the first 10000 numbers.

So...the probability of selecting one perfect square is 100/10000 = 1/100 = 1%

y=-x+5 and 5x+2y=14   substituting for y in the seconf equation, we have

5x + 2(-x + 5) = 14       simplify

5x - 2x + 10 = 14

3x + 10 = 14                 subtract 10 from both sides

3x = 4                           divide both sides by 3

x = 4/3

And y = -(4/3) + 5 = 11/3

So...the solution is  (4/3, 11/3)

Thank you!         

$${\mathtt{\,-\,}}\left({\mathtt{8}}{\mathtt{\,\times\,}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)\right) = {\mathtt{6}}$$

There is the answer....

In what????

Thank you!

I agree with tiddle

Wow!!!...nice Tiddle   .....!!!!