Notice xvxvxv, that x cannot be 0 in the denominator
For the function iside the root....it must be > 0
Here's it's graph...........https://www.desmos.com/calculator/mfb0scvufp
The two points where this = 0 are at ±(1/√2)......then note, that on [-1/√2, 1/√2], this function is ≤ 0
So....the domain appears to be (-∞, -1/√2) U ( 1/√2, ∞ )