I'll do this one with vectors
S83°E = 353°
E20°N = 20°
So, the first vector is <375cos353 , 375sin353 > ....and the second vector is <42cos20, 42sin20>
So the x component of the resultant vector is 375cos353 + 42cos20 = about 411.67
And the y component of the resultant vector is 375sin353 + 42sin20 = about -31.336
And the magnitude of the resultant vector = √[(411.67)^2 + (-31.336)^2] = about 412.86
And the angle of the resultant is given by
tan-1 (-31.336 / 411.67) = about -4.35° = 355.65° = S85.65°E (in terms of heading)
So....the speed of the drone is 412.86 mph in the direction of S85.65°E
IT IS WEIRD
. Tell you when im back.
