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Well for starters csc cannot be equal to any number of degrees because cosec is  hyp over opp.  It cannot be in degrees.

now you can find cosec òf 79.4 degrees..  

That would be 1/sine of 79.4 degrees

1/sin(79.4)

Or on this calc I think you can enter it as csc(79.4)

Make sure the calc is set to degrees.

note: sometimes I have called it csc and other times cosec.  They are the same thing.

Ask gently.

10+9=19

I think it's question on calculation with time.

Then it should be 8:10.

She is 94 years old

19:70 or just 19.7

Dividing two numbers with the same signs produces a positive......dividing two numbers wth different signs produces a negative.

My Ti-89 got $${\mathtt{\,-\,}}\left({\mathtt{6}}{\mathtt{\,\times\,}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,-\,}}{\mathtt{7}}\right)}^{{\mathtt{2}}}\right)$$. I am not sure why we are getting different answers. 

Last time I did calculus was in 2009. 

But here is a complete work through and a calculator you can use on line, which gave the same as my TI-89

https://www.symbolab.com/solver/derivative-calculator/%5Cfrac%7Bd%7D%7Bdb%7D%5Cleft(%5Cleft(7-2b%5Cright)%5E%7B3%7D%5Cright)/?origin=button

The additive inverse property of addition.

1/2 *(2 1/6 + 7/8)

Note that 2 + 1/6 = 13/6  ... so we have

1/2 ( 13/6 + 7/8)      and the common denominator between 6 and 8 is 24....so we have

1/2 (52/24 + 21/24) =

1/2(73/24) =

73/48

what kind of services you need?

im as positive as 1 plus 0

it simplifies to a number

math is something that has to do with numbers.

Prime factor 648.

$${\frac{{\mathtt{648}}}{{\mathtt{2}}}} = {\mathtt{324}}$$

$${\frac{{\mathtt{324}}}{{\mathtt{2}}}} = {\mathtt{162}}$$

$${\frac{{\mathtt{162}}}{{\mathtt{2}}}} = {\mathtt{81}}$$

$${\frac{{\mathtt{81}}}{{\mathtt{3}}}} = {\mathtt{27}}$$

$${\frac{{\mathtt{27}}}{{\mathtt{3}}}} = {\mathtt{9}}$$

$${\frac{{\mathtt{9}}}{{\mathtt{3}}}} = {\mathtt{3}}$$

$${{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{3}}}^{{\mathtt{4}}} = {\mathtt{648}}$$

2^3 can be rewritten as 2^2 * 2^1, one 2 stays in the radical. 

3^4 can be taken completely taken out of the radical as 9. 

Which becomes 2*9 √2 or 18*√2

Use the divison rule for exponents. 

$${\frac{{{\mathtt{x}}}^{{\mathtt{m}}}}{{{\mathtt{x}}}^{{\mathtt{n}}}}} = {{\mathtt{x}}}^{\left({\mathtt{m}}{\mathtt{\,-\,}}{\mathtt{n}}\right)}$$

Just like when you write a fraction in simplest form ie $${\frac{{\mathtt{3}}}{{\mathtt{2}}}}$$, we rewrite this as 1 1/2.

In the final answer we can not report negitive exponents.
We take the smallest exponent across the divisor bar and subtract from the quanity currently there. 

For example: $${{\mathtt{\,-\,}}{\mathtt{x}}}^{-{\mathtt{1}}}$$ can be rewritten as $${\frac{\left({{\mathtt{\,-\,}}{\mathtt{x}}}^{-{\mathtt{1}}}\right)}{{{\mathtt{x}}}^{{\mathtt{0}}}}}$$ then we move -1 across the divisor bar because it is less than 0, then we have $${\mathtt{\,-\,}}{\frac{\left({\mathtt{1}}\right)}{\left({{\mathtt{x}}}^{\left({\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}\right)}}$$ you are now asking why is it $${{\mathtt{x}}}^{\left({\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}$$, it is because when we subtract a negitive number we actually add it. Which makes it,$${\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{{\mathtt{x}}}^{{\mathtt{1}}}}}$$, since we don't normally express 1 as an exponent.  

Which makes our final answer:

$${\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{x}}}}$$

Very nice, Anonymous.....!!!

(2X^-2 * y^3)^4 * 2x^19 * y^6

So we have

2^4 * (x^-2)^4 * (y^3)^4 * 2x^19 * y^6      remember ..  (a^m)^n  = a ^(m *n)

16 * x ^-8 * y^12 *2x^19 * y^6   rearrange

(16*2 ) * ( x^-8 * x^19) * (y^12 * y^6)       and  a^m * a^n = a^(m + n)

32*x^11*y^18

Divide 97 by 2. This will be your baseline. 

$${\frac{{\mathtt{97}}}{{\mathtt{2}}}} = {\mathtt{48.5}}$$

Now, start by dividing 97 by each succesive prime number. 

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41 , 43, 47

Skip 3 because 9 + 7 which is not a multiple of 3. 

Skip 5 because 97 does not end in 5.

$${\frac{{\mathtt{97}}}{{\mathtt{7}}}} = {\mathtt{13.857\: \!142\: \!857\: \!142\: \!857\: \!1}}$$ 

$${\frac{{\mathtt{97}}}{{\mathtt{11}}}} = {\mathtt{8.818\: \!181\: \!818\: \!181\: \!818\: \!2}}$$

$${\frac{{\mathtt{97}}}{{\mathtt{13}}}} = {\mathtt{7.461\: \!538\: \!461\: \!538\: \!461\: \!5}}$$

We already know that no prime number below 7 works, because the quotient of 97/13 is 7 and there are no prime numbers less than 7 that will work. So we can conclude that 97 is indeed prime. 

16!!!!!!!!