All Answers 358172 Answers

Sorry. I Dont Know.

Thanks Chris,

I'm all confused, algegraically what you say seems correct but look at the pic.

I think the answer is  (0,0), (1,2) and (-1,2)My algebra is slightly diff from your but I get the same answer - i am sure it is wrong. 

It's doing my head in - I am going to take a break.  :))

Thanks, kitty<3....I see now what is meant....I couldn't make heads or tails of it...!!!

*waiting*        

When i move on to 6th ill be in theater arts!

How much did you like it on a scale of 1 to 10?

Tell melody that this is finished i know she has been waring for one.

More drama from jillybean....!!!

Good observation.

The way I interpreted it, the man wants to make a 20% profit on the bag after the 15 discount.

In this case, you would first find what 20% profit on $30 is, and then find what the total would be before the 15% discount:

So:

20% * $30 + $30

= 1.2 * 30

= 36

So the man would need to sell the bag for a final price of $36, after the discount.

Therefore, we now need to find the price of the bag before the 15% discount, which we can call x:

x - 0.15x = 36

0.85 x = 36

x =42.35

So he needs to sell it for $42.35 before the discount, or $36 after the discount.

Just use "FOIL" as you normally would.....

Always welcome! :D

While the cosine of a given angle is used to find the ratio of its opposite side / hypotenuse, the arccosine does the opposite: it finds the measure of an angle from the given ratio of its opposite side / hypotenuse.

For example,  $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{45}}^\circ\right)} = {\frac{{\sqrt{{\mathtt{2}}}}}{{\mathtt{2}}}}$$

So $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}^{\!\!\mathtt{-1}}{\left({\frac{{\sqrt{{\mathtt{2}}}}}{{\mathtt{2}}}}\right)} = {\mathtt{45}}$$

So if you had the lengths of the opposite side and the hypotenuse for a right triangle, you would use arccosine to find the measure of the angle.

Thanks,  kitty<3 ....!!!

Just do 87/100 and simplify

Let N be the cost before the markup

N(1.4) = 99.99     divide by 1.4 on both sides

N = 99.99/1.4 = about $71.42

On the site calculator (and most other calculators as well) press "2nd" then the regular sin, cos, and tan buttons.

For example, if you wanted the arcsin of 1/2, you would enter "2nd", "sin" and 1/2.

Another way would be to enter "asin(1/2)" into the site calculator.

9x^3/5=72   multiply both sides by 5

9x^3  = 360   divide by 9 on both sides

x^3  = 40       take the cube root of both sides

x = ³√(40) = ³√(8 * 5)  = (2)³√5

At 45 degrees and every ± 180 degrees after that

C(6,2) =  15 different combos

LOL!!!...don't shoot the messenger just because the message is unpleasant....!!!

Chris tells me that Desmos is not fully compatible with Firefox.  Major Bummer !!!!!

He says if you use the screen keypad instead of your normal keypad it works fine.

He said it will stuffs up other things as well as Desmos if I use my normal keyboard.

Thanks for the feedback Chris. 

[ I'd smile but I don't like your assessment - we need a half smile in here :)) ]

Cool graphics, Mel  ....this visual really helps to see what is going on...!!!

Does anyone know how to get Geogebra to make a right angle with a little box ? 

I have never seen it done but it would be wanted often. 

Let N be the number of minutes when the planes are at the same altitude..so we have

520 +40N = 3800 - 120N      add 120N to both sides.....subtract 520 from both sides

160N = 3280                        divide both sides by 160

N = 20.5 minutes

Thanks Chris, I just wanted to give a visual. 

I have not marked right angles as that took too much space but the intenal intervals are all altitudes (have right angles)

I have not included all the working, just the main steps. 

1)  Equation of EC is      x=5

2)  Gradient of AC = 2

3)  Gradient of  DB = -1/2

4)  Equation of DB       m=-1/2      B(7,3)

      y=(-x+13)/2

5)  On linterval  DB         When x=5     y=4

6)  Intersection of DB and EC is   (5,4)

Orthocentre is (5,4) 

You could check this by finding the equation of AF and checking that (5,4) satisfies this equation.

Square root of x minus 5+7=11 is equal to x=3.