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The first section can be written as ₇C₂ · ₅C₄ / ₁₂C₆

 ₇C₂ is evaluated as 7! / (2! · 5!) which can be reduced to 7·6 / (2·1)  =  42 / 2  =  21.

 ₅C₄ is evaluated as 5! / (4! · 1!) which can be reduced to 5 / (1)  =  5.

 ₁₂C₆ is evaluated as 12! / (6! · 6!) which can be reduced to 11·3·4·7 / (1)  =  924.

In general, _nC_r becomes n! / ( r! · (n - r)! ), so write 12! / (6! · 6!) as

(12·11·10·9·8·7·6·5·4·3·2·1) / ( 6·5·4·3·2·1 · 6·5·4·3·2·1 ) and then cancel like mad!

Questions?

 if you do 10:20 then it would be a ratio.

 it is 452.16

 it is 19

 i found my answer and it is 35.66666667 

plus i did it on a clacture

(2*pi*r*360)/(length of the arc in degrees)

Not possible to answer. an odd+odd+odd will still equal an odd number which is impossible as 30 is an even number

19

Thanks! :)

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11  anedaaa thendy

Finish it all in one day!

It would actually be 150 miles apart. 

3/.5*25=150

21 is the answer

Take 2.71828 to the 60.12th power, then multiply it with 1,000.

A would equal 12,875,576,667,653,751*10^13, or 12,875,576,667,653,7510000000000000

If you read about 4-5 pages a day, you should be able to finish reading it within 2 weeks.

8.1x10(6) <--- 6 is suppose to be an expont 

It will cost 406$ for gas.

X would equal 4

x=4

It depends on what earlier identities that you are allowed to assume.

From basics,

sin(A+B) = sinA.cosB + cos A.sinB, and sin(A-B) = sinA.cosB - cosA.sinB

(or do we have to derive these ?)

Adding, sin(A+B)+sin(A-B) = 2sinA.cosB.

Now let A+B = C and A-B = D, then A=(C+D)/2 and B=(C-D)/2,

so sinC + sinD = 2sin((C+D)/2).cos((C-D)/2).   (Are we allowed to assume this ?)

Now go through a similar routine starting with cos(A+B) and cos(A-B), to arrive at

cosC + cosD = 2cos((C+D)/2).cos((C-D)/2).

Apply these two identities to the lhs of your problem identity and the rhs (for the positive sign) drops out.

To deal with the negative sign in the middle, repeat the calculation starting with sin(A+B) - sin(A-B).

Given that it's a quadratic with zeros x1 and x2, the best that you can do is to say that the equation is

y = k(x - x1)(x - x2), where k is some non-zero constant, positive or negative.  If k is positive the graph will be concave up, if negative it will be concave down. You have an infinite number of possibilities.