Solve for x: -6 = -2 (x+3) -6 = -2 (x+3) is equivalent to -2 (x+3) = -6: -2 (x+3) = -6 Divide both sides of -2 (x+3) = -6 by -2: (-2 (x+3))/(-2) = (-6)/(-2) (-2)/(-2) = 1: x+3 = (-6)/(-2) The gcd of -6 and -2 is -2, so (-6)/(-2) = (-2×3)/(-2×1) = (-2)/(-2)×3 = 3: Answer: | | x+3 = 3 x=0
Use the formula: F=G.M.M/r^2, where G=Newton's gravitational constant, M=mass of the bowling b***s, r=the distance between them.
40*5/8=200/8=25
9x-9= -9
9x=-9+9
9x=0 divide both sides by 9
x=0/9
x=0
Solve for Z: Z^4 = -(3 i)-5 -(3 i)-5 = -5-3 i: Z^4 = -5-3 i Taking 4^th roots gives (-5-3 i)^(1/4) times the 4^th roots of unity: Answer: | | Z = -(-5-3 i)^(1/4) or Z = -i (-5-3 i)^(1/4) or Z = i (-5-3 i)^(1/4) or Z = (-5-3 i)^(1/4)
a = 1/4 (49-3 sqrt(249)) = 0.415200 and b = 1/4 (49+3 sqrt(249)) = 24.0848
a = 1/4 (49+3 sqrt(249)) = 24.0848 and b = 1/4 (49-3 sqrt(249)) = 0.415200
Solve the following system: {x+2 y = 20 | (equation 1) y+2 z = 9 | (equation 2) 2 x+z = 22 | (equation 3) Swap equation 1 with equation 3: {2 x+0 y+z = 22 | (equation 1) 0 x+y+2 z = 9 | (equation 2) x+2 y+0 z = 20 | (equation 3) Subtract 1/2 × (equation 1) from equation 3: {2 x+0 y+z = 22 | (equation 1) 0 x+y+2 z = 9 | (equation 2) 0 x+2 y-z/2 = 9 | (equation 3) Multiply equation 3 by 2: {2 x+0 y+z = 22 | (equation 1) 0 x+y+2 z = 9 | (equation 2) 0 x+4 y-z = 18 | (equation 3) Swap equation 2 with equation 3: {2 x+0 y+z = 22 | (equation 1) 0 x+4 y-z = 18 | (equation 2) 0 x+y+2 z = 9 | (equation 3) Subtract 1/4 × (equation 2) from equation 3: {2 x+0 y+z = 22 | (equation 1) 0 x+4 y-z = 18 | (equation 2) 0 x+0 y+(9 z)/4 = 9/2 | (equation 3) Multiply equation 3 by 4/9: {2 x+0 y+z = 22 | (equation 1) 0 x+4 y-z = 18 | (equation 2) 0 x+0 y+z = 2 | (equation 3) Add equation 3 to equation 2: {2 x+0 y+z = 22 | (equation 1) 0 x+4 y+0 z = 20 | (equation 2) 0 x+0 y+z = 2 | (equation 3) Divide equation 2 by 4: {2 x+0 y+z = 22 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = 2 | (equation 3) Subtract equation 3 from equation 1: {2 x+0 y+0 z = 20 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = 2 | (equation 3) Divide equation 1 by 2: {x+0 y+0 z = 10 | (equation 1) 0 x+y+0 z = 5 | (equation 2) 0 x+0 y+z = 2 | (equation 3) Collect results: Answer: | | {x = 10 y = 5 z = 2
No it doesn't (3 1/2)^2 = (7/2)^2 = 49/4 = 12 1/4
or another way (3 1/2)^2 = (3 + 1/2)^2 = (3+1/2)(3+1/2) = 9 + 1/2(3) + 1/2(3) + 1/2(1/2) = 9 + 3 + 1/4 = 12 1/4
what do you mean by formula mass?
Divede numerator by 3 and denominator by 3
12/1287
Divide by 3 again
4/429 As an aside: If you add the digits of a number and the result is a number divisible by three, then the original number is divisible by three also (that is what I did here)
Is it? It is! It felt like a Monday to me this morning.
It means: 6.6666666666666667 X 10^25
It looks like you are trying to calculate a monthly payment on a loan of $8,700 @ 9.31% compounded monthly over a period of 3.5 years.
Your answer should be $243.52. Good luck.
(3x/4) + (2x/3)=51
9x/12 + 8x/12=51
17x/12=51 cross multiply
17x=612 divide both sides by 17
x=612/17
x=36
hi the answer to 15 + 19 =34
thanks!
what does the n stand for n+13=75
n + 13=75
n=75-13
n=62
Solve for x: (17 x)/12 = 51 Multiply both sides of (17 x)/12 = 51 by 12/17: ((12×17 x)/(17))/(12) = 12/17×51 12/17×51 = (12×51)/17: (12×17 x)/(17×12) = (12×51)/17 (12×17 x)/(17×12) = (17×12)/(17×12)×x = x: x = (12×51)/17 51/17 = (17×3)/17 = 3: x = 12×3 12×3 = 36: Answer: | | x = 36
That is NOT an equation! What are you trying to calculate? It looks like compound interest? let us know what you want to calculate.
It is 2.875
LOOK IT UP IN YOUR CHEMISTRY BOOK.
447+123=570
