5x@Sup{2}-39x-512
Does this mean: 5 x^2-39 x-512 = 0???????????, if yes, then we have:
Solve for x:
5 x^2-39 x-512 = 0
Divide both sides by 5:
x^2-(39 x)/5-512/5 = 0
Add 512/5 to both sides:
x^2-(39 x)/5 = 512/5
Add 1521/100 to both sides:
x^2-(39 x)/5+1521/100 = 11761/100
Write the left hand side as a square:
(x-39/10)^2 = 11761/100
Take the square root of both sides:
x-39/10 = sqrt(11761)/10 or x-39/10 = -sqrt(11761)/10
Add 39/10 to both sides:
x = 39/10+sqrt(11761)/10 or x-39/10 = -sqrt(11761)/10
Add 39/10 to both sides:
Answer: | x = 39/10+sqrt(11761)/10 or x = 39/10-sqrt(11761)/10
