Yes you are right, 40 minutes is what I've got.
in 1000 they can build a building
i dunt kno
??/
r u looken up er down
yo ugli I's
whats up guys
wat up wit dos I's???
Dat yo reel phota?
Hiiii
it is a 30 60 90 triangle: x,x sqrt(3),2x
60 is the opossite of 9 (x sqrt(3))
9/sqrt(3) = 5.1961524227066319 or 3sqrt(3) is opposite of 30 (x)
6sqrt(3) the opposite of 90 (2x)
Of course I am! (just kidding...)
"The world won't be destroyed by those who do evil, but by those who watch them without doing anything."
Albert Einstein
Hmm. For some reason, I got 1000. O_O
u bettu thenk me cos i dA une who tell hur da answur to de quesshion...
she copee it frum me
Aw, You're Welcome!! :)
\(\begin{array}{lcl} p\approx 2\pi\sqrt{\frac12 (a^2+b^2)} \qquad a \text{ and } b \text{ are the half-axes !!!} \\ \text{ so } a = \frac{w}{2} \text{ and } b = \frac{h}{2} \\ \text{ we have } p\equiv 2\pi\sqrt{\frac12 [ (\frac{w}{2})^2 + (\frac{h}{2})^2 ] } \end{array} \\ \begin{array}{lcl} p &\approx& 2\pi\sqrt{\frac12 [ (\frac{w^2}{4}) + (\frac{h^2}{4}) ] }\\ p &\approx& 2\pi\sqrt{\frac12 (\frac{w^2+h^2}{4}) }\\ p &\approx& 2\pi\sqrt{\frac24 (\frac{w^2+h^2}{4}) }\\ p &\approx& 2\pi \cdot \frac{1}{4} \sqrt{2\cdot (w^2+h^2 ) }\\ p &\approx& \frac{\pi}{2}\cdot \sqrt{2\cdot (w^2+h^2 ) }\\ \end{array} \)
jut lik U copie pepl photo???
#get rekt
115v
if you go 237 feet in 3 sec. how many mile per hour are you going
237/3
= 79MPH.
203.561 miles per hour
3x=15
x=5
Okay, Thanks everyone! I'll Question it. Thanks everyone for your time, and your help. I greatly appreciated it!
This is why I like to be on here. I get help from wonderful people. ( except from that frog person...)
