All Answers 358090 Answers

my mistake 

DS!!!........how goes it??

We can solve this with a proportion........note....5ft = 60in........so we have

60/ 2  = x / 3      where x is the actual tent length.....cross- multiply

180x  =  2x       divide both sides by  2

x = 90  in.   =    7 + 1/2 ft

whats 490 into 5e

e=2.718281828...........................

490/ [5 X 2.718281828]=36.0522.........

do you get it? 

 .................................................................................................Really???.....

Thats funnyy

     NO

49,600,000 m=4.96 X 10^7m

the answer is 50

1.8 in fraction form

1.8 X 10/10=

18/10= divide both sides by 2

9/5=1 4/5

Ok.

To open a square brackets follow this 

1 - square the first term    ( in this question the first term is " 3x " so \((3x)^2 = 3^2*x^2 = 9x^2 \)) 

2 - Multiply the power which is alwayse " 2 " with the two terms ( In this qestion \(2 * 3x * -3 = -18x \) ) 

3 - square the second term ( In this question the second term is " -3 " so \((-3)^2 = 9 \)

4 - gather your answer 

\((3x-3)^2 = 9x2 - 18x + 9 \)

how do you wrkout 10[-x(y)]=10 X (-xy)=-10xy

13>9+x subtract 9 from both sides

4 >  x reverse the inequality

x < 4

Your welcome, but try to do better next time :)

Even though you won't be held back, next year your going to have to take that class again. :(

Thank you!  It's the end of the term/semester and I was just wondering.

\(\sum F = ma\)

\(a= \frac{\sum F}{m}\)

\(a = \frac{40}{40}\)

\(a = 1 \frac{m}{s^2}\)

(3x-3)^2 expand

9x^2 - 18x + 9

no I'm not sure how you got to the answer

To solve when the unknown is an exponent, find the log (either base ten or base e) of both sides:

y = 3^x

log(y)  =  log(3^x)

log(y)  =  xlog(3)                          <since exponents become multipliers>

log(y) / log(3)  =  x                       <divide both sides by log(3)>

You can use either log or ln; if you used ln, your answer is:  ln(y) / ln(3)  =  x

Do you understand how I opened the brackets  ??

\((3x-3)^2 = 9x^2-18x+9\)

Solve for x:
y = 3^x

y = 3^x is equivalent to 3^x = y:
3^x = y

Take the logarithm base 3 of both sides:
Answer: | x = (log(y))/(log(3))  for y > 0

I think you have to fail like, 3 classes to get held back

t = d/r = 7.4e18/1e16
t = 7.4e2
t = 740 years